在Python中，有没有一种方法可以通过Pandas数据帧中的SMTPLib将电子邮件连接到多个收件人？

我有下面的代码发送特定于特定地址的电子邮件，所有这些都在一个数据框中。型号为pandas.series。我如何才能发送包含多个地址的每个列表？有些电子邮件地址最多有8个，用分号（；）分隔。发送的唯一可能性是发送到单个地址。从下面的数据框中，我能够发送特定于ID的电子邮件，以测试邮件值。电子邮件没什么用。我得到以下错误：

SMTPRecipientsRefused: {'': (421, b'4.7.0 Too many protocol errors (6) on this connection, closing transmission channel.')}

数据帧df

IDs  CompanyNames     Emails                                        TestEmail
2003    XXX           xx@gmail.com;yy@ryt.com;dd@xx.com;ii@dd.com    kk@kk.com
2004    XXXYY         xx@gmail.com;yy@ryt.com;dd@xx.com              kk@kk.com
2005    XXTTNN        xx@gmail.com;yy@ryt.com;dd@xx.com;ii@dd.com    kk@kk.com
2006    BBOOLL        xx@gmail.com;yy@ryt.com                        kk@kk.com

代码如下。对于单个地址，我可以将名称与df['id']值匹配的附件发送到相应的电子邮件地址

import smtplib, ssl
from email.message import EmailMessage
import getpass

ids = df['IDs']
emails_to = df['Emails'] #Pandas column with email addresses split  by semi-colon(;)
namesofcompanies  = df["CompanyNames"]
sendfrom  = df["SenderList"]

date_7days = (datetime.now() + timedelta(days=7)).strftime('%d/%m/%Y')
date_14days = (datetime.now() + timedelta(days=13)).strftime('%d/%m/%Y')

email_pass = input() #Office 365 password 
context=ssl.create_default_context()
for i in range(len(emails_to)): # iterate through the records
    # for every record get the name and the email addresses
    ID = str(ids[i])
    Emaitstosendto = emails_to[i]
    companynames = namesofcompanies[i]
    tosendfrom = sendfrom[i]
    
    if my_files_dict.get(ID): #Looks for  attachments in the same folder with same name  as the corresponding record 
        smtp_ssl_host = 'smtp.office365.com'
        smtp_ssl_port = 587
        email_login = "xxx@xxx.com" #Office 365 email  
        email_from = tosendfrom         
        email_to = Emaitstosendto
        
        msg = MIMEMultipart()
        msg['Subject'] = "Received Emails between "+date_7days+" - "+date_14days
        msg['From'] = email_from
        msg['To'] = email_to
        msg['X-Priority'] = '2'    
         
        text = ("XXXX,\n"                
                f"xxxxxx\n\n")
        
        msg.attach(MIMEText(text))
        filename = my_files_dict.get(ID)#Files in the folder matching the ID   
        fo = open(filename,'rb')

        s2 = smtplib.SMTP(smtp_ssl_host, smtp_ssl_port)
        s2.starttls(context=context)
        s2.login(email_login, email_pass) 
        attachment = email.mime.application.MIMEApplication(fo.read(),_subtype="xlsx")
        fo.close()
        attachment.add_header('Content-Disposition','attachment',filename=filename)

        msg.attach(attachment)        
        s2.send_message(msg)        
        s2.quit()  

从这个答案中可以看出：

这是您必须更改的行：

首先将要发送的电子邮件拆分为不同电子邮件的列表，然后使用“，”加入

msg['To'] = ", ".join(email_to.split(";"))