Python&；Excel连接

如何连接第27行？我得到“TypeError:无法连接'str'和'list'对象”。这是因为我在符号列表中使用了一个变化的变量吗

这就是我所说的一句话：

ws.cell(1,i+1).value =  "The price of" + symbolslist[i] + " is " + price 

下面是我的代码和第27行的重写

from openpyxl import Workbook

import urllib
import re

from openpyxl.cell import get_column_letter

wb = Workbook()

dest_filename = r'empty_book.xlsx'

ws = wb.create_sheet()

ws.title = 'Stocks'
symbolslist = ["aapl","spy","goog","nflx"] 

i=0
while i<len(symbolslist):
    #counts each object as 1 in the list
    url = "http://finance.yahoo.com/q?s="+symbolslist[i]+"&q1=1"
    htmlfile = urllib.urlopen(url)
    htmltext = htmlfile.read()
    regex = '<span id="yfs_l84_'+symbolslist[i]+'">(.+?)</span>'
    pattern = re.compile(regex)
    price = re.findall(pattern,htmltext)
    print "The price of", symbolslist[i], " is ", price 
    ws.cell(1,i+1).value =  "The price of" + symbolslist[i] + " is " + price 
    i+=1


wb.save(filename = dest_filename)

来自openpyxl导入工作簿的

导入URL库
进口稀土
从openpyxl.cell导入获取列字母
wb=工作簿（）
dest_filename=r'empty_book.xlsx'
ws=wb.create_sheet（）
ws.title=‘股票’
符号列表=[“aapl”、“spy”、“goog”、“nflx”]
i=0
而i
re.findall（）
总是返回一个列表；也许你想把它变成一个字符串：

ws.cell(1,i+1).value = "The price of" + symbolslist[i] + " is " + ','.join(price)

或者，仅打印第一个元素：

ws.cell(1,i+1).value = "The price of" + symbolslist[i] + " is " + price[0]

使用HTML解析器解析HTML更容易；将是一个更好的工具：

import urllib
from bs4 import BeautifulSoup

for symbol in symbolslist:
    url = "http://finance.yahoo.com/q?s={}&q1=1".format(symbol)
    response = urllib.urlopen(url)
    soup = BeautifulSoup(response, from_encoding=response.headers.getparam('charset'))
    price = soup.find('span', id='yfs_l84_' + symbol).text
    text = "The price of {} is {}".format(symbol, price)
    print text
    ws.cell(1,i+1).value = text

快速演示：

>>> import urllib2
>>> from bs4 import BeautifulSoup
>>> symbolslist = ["aapl","spy","goog","nflx"] 
>>> for symbol in symbolslist:
...     url = "http://finance.yahoo.com/q?s={}&q1=1".format(symbol)
...     response = urllib.urlopen(url)
...     soup = BeautifulSoup(response, from_encoding=response.headers.getparam('charset'))
...     price = soup.find('span', id='yfs_l84_' + symbol).text
...     text = "The price of {} is {}".format(symbol, price)
...     print text
... 
The price of aapl is 483.03
The price of spy is 168.89
The price of goog is 872.35
The price of nflx is 327.26

re.findall（）
始终返回列表；也许你想把它变成一个字符串：

ws.cell(1,i+1).value = "The price of" + symbolslist[i] + " is " + ','.join(price)

或者，仅打印第一个元素：

ws.cell(1,i+1).value = "The price of" + symbolslist[i] + " is " + price[0]

使用HTML解析器解析HTML更容易；将是一个更好的工具：

import urllib
from bs4 import BeautifulSoup

for symbol in symbolslist:
    url = "http://finance.yahoo.com/q?s={}&q1=1".format(symbol)
    response = urllib.urlopen(url)
    soup = BeautifulSoup(response, from_encoding=response.headers.getparam('charset'))
    price = soup.find('span', id='yfs_l84_' + symbol).text
    text = "The price of {} is {}".format(symbol, price)
    print text
    ws.cell(1,i+1).value = text

快速演示：

>>> import urllib2
>>> from bs4 import BeautifulSoup
>>> symbolslist = ["aapl","spy","goog","nflx"] 
>>> for symbol in symbolslist:
...     url = "http://finance.yahoo.com/q?s={}&q1=1".format(symbol)
...     response = urllib.urlopen(url)
...     soup = BeautifulSoup(response, from_encoding=response.headers.getparam('charset'))
...     price = soup.find('span', id='yfs_l84_' + symbol).text
...     text = "The price of {} is {}".format(symbol, price)
...     print text
... 
The price of aapl is 483.03
The price of spy is 168.89
The price of goog is 872.35
The price of nflx is 327.26

re.findall（）
返回一个列表。它抱怨的是
price
，而不是
symbolslist
re.findall（）
返回一个列表。它在抱怨
price
，而不是
symbolslist
。如何将re.findall（）更改为字符串？@RobB.：通过获取第一个元素或将所有元素合并为一个字符串。我已经给出了这两个选项的示例。如何将re.findall（）更改为字符串？@RobB.：通过获取第一个元素或将所有元素合并为字符串。我已经给了你两种选择的例子。