在python中实现ZeroDivisionError异常

所以，说到编程，我是一个彻头彻尾的傻瓜，只是在周末才开始学习python。无论如何，作为一个来自Youtube教程的挑战，我想写一个程序，可以找到定义范围内的所有数字，当除以4时，将给我0提醒，然后它们将被列出。所以我把它放远一点，下面是我到目前为止得到的

# Program that let's you find all numbers in any range defined by user
# that can be divided without any reminder by the number also defined by user

print('Find all numbers in range...')

while True:
    try:
        x = int(input('From: ')) # begining of the range
        y = int(input('.. to: ')) # end of the range
        z = int(input('.. that can be divided by: ')) # value of the number to divide by
    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue

    for a in range(x, y):
        try:
            if a % z == 0:
                print(a, [a / z], end = ' ') 
        except ZeroDivisionError: # issue with implementing this exception
            pass

当我不再使用pass语句时，我尝试

print('You can\'t divide by 0!!') # or similar

---

它打印字符串（x，y）次。有什么建议吗？非常感谢您可以尝试在下面的示例中引发异常检查

#!/usr/bin/env python3

print('Find all numbers in range...')

while True:
    try:
        x = int(input('From: ')) # begining of the range
        y = int(input('.. to: ')) # end of the range
        z = int(input('.. that can be divided by: ')) # value of the number to divide by
    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue

    for a in range(x, y):
        try:
            if a % z == 0:
                print(a, [a / z]) 
        except ZeroDivisionError as err: # issue with implementing this exception
            raise Exception("Cannot divide by zero", err)

---

您可以尝试在下面的示例中引发异常检查

#!/usr/bin/env python3

print('Find all numbers in range...')

while True:
    try:
        x = int(input('From: ')) # begining of the range
        y = int(input('.. to: ')) # end of the range
        z = int(input('.. that can be divided by: ')) # value of the number to divide by
    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue

    for a in range(x, y):
        try:
            if a % z == 0:
                print(a, [a / z]) 
        except ZeroDivisionError as err: # issue with implementing this exception
            raise Exception("Cannot divide by zero", err)

---

问题是您正在for循环中尝试/排除。如果不希望程序在遇到异常时终止，只需在打印警告后中断循环即可

print('Find all numbers in range...')

while True:
    try:
        x = int(input('From: ')) # begining of the range
        y = int(input('.. to: ')) # end of the range
        z = int(input('.. that can be divided by: ')) # value of the number to divide by
    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue

    for a in range(x, y):
        try:
            if a % z == 0:
                 print(a, [a / z], end = ' ') 
        except ZeroDivisionError:
            print ("Cannot divide by zero")
            break

---

问题是您正在for循环中尝试/排除。如果不希望程序在遇到异常时终止，只需在打印警告后中断循环即可

print('Find all numbers in range...')

while True:
    try:
        x = int(input('From: ')) # begining of the range
        y = int(input('.. to: ')) # end of the range
        z = int(input('.. that can be divided by: ')) # value of the number to divide by
    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue

    for a in range(x, y):
        try:
            if a % z == 0:
                 print(a, [a / z], end = ' ') 
        except ZeroDivisionError:
            print ("Cannot divide by zero")
            break

---

你如何回答自己的问题？所以我尝试了一件我以前没有尝试过的事情，我用了break语句和vuala来代替pass。接下来，我将尝试将结果写入一个简单的.txt文件中，以下是迄今为止的代码供感兴趣的人使用

# Program that let's you find all numbers in any range defined by user
# that can be divided without any reminder by the number also defined by user

print('Find all numbers in range...')

while True:
    try:
        x = int(input('From: ')) # begining of the range
        y = int(input('.. to: ')) # end of the range
        z = int(input('.. that can be divided by: ')) # value of the number to divide by
    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue

    for a in range(x, y):
        try:
            if a % z == 0:
                print(a, [a / z], end = ' ')
        except ZeroDivisionError: # in case of variable z = 0
            print('You shoudln\'t divide by 0!!')
            break
    break

---

你如何回答自己的问题？所以我尝试了一件我以前没有尝试过的事情，我用了break语句和vuala来代替pass。接下来，我将尝试将结果写入一个简单的.txt文件中，以下是迄今为止的代码供感兴趣的人使用

# Program that let's you find all numbers in any range defined by user
# that can be divided without any reminder by the number also defined by user

print('Find all numbers in range...')

while True:
    try:
        x = int(input('From: ')) # begining of the range
        y = int(input('.. to: ')) # end of the range
        z = int(input('.. that can be divided by: ')) # value of the number to divide by
    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue

    for a in range(x, y):
        try:
            if a % z == 0:
                print(a, [a / z], end = ' ')
        except ZeroDivisionError: # in case of variable z = 0
            print('You shoudln\'t divide by 0!!')
            break
    break

---

您可以在进入循环之前验证用户输入的除数。然后，不需要检查for循环中是否存在零除错误：

while True:
    try:
        x = int(input('From: '))
        y = int(input('.. to: '))

        z = int(input('.. that can be divided by: '))
        if z == 0:
            print('You can\'t divide by 0!!')
            continue            

    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue

    for a in range(x, y):
        if a % z == 0:
            print(a, [a / z], end = ' ')
    print()

---

您可以在进入循环之前验证用户输入的除数。然后，不需要检查for循环中是否存在零除错误：

while True:
    try:
        x = int(input('From: '))
        y = int(input('.. to: '))

        z = int(input('.. that can be divided by: '))
        if z == 0:
            print('You can\'t divide by 0!!')
            continue            

    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue

    for a in range(x, y):
        if a % z == 0:
            print(a, [a / z], end = ' ')
    print()

---

在代码中，捕获

ZeroDivisionError

的唯一方法是变量

z

的内容为0。此时，我注意到您的代码中存在一些问题：

在将x和y传递给

range（）

函数之前，应确保

x

您应该始终确保

z

不为null，然后脚本将检查它是否可以按您希望的方式进行分割

以下是我的建议：

# Program that let's you find all numbers in any range defined by user
# that can be divided without any reminder by the number also defined by user

print('Find all numbers in range...')

while True:
    try:
        x = int(input('From: ')) # begining of the range
        y = int(input('.. to: ')) # end of the range
        z = int(input('.. that can be divided by: ')) # value of the number to divide by
    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue
    numbers = range(x, y)
    if len(numbers) > 0 and z != 0:  #Check if the list is empty and if the divider is not null
        for number in numbers:
            if number % z == 0:
                print(number, [number / z])
    else:
        print("Invalid numbers passed")`

---

在代码中，捕获

ZeroDivisionError

的唯一方法是变量

z

的内容为0。此时，我注意到您的代码中存在一些问题：

在将x和y传递给

range（）

函数之前，应确保

x

您应该始终确保

z

不为null，然后脚本将检查它是否可以按您希望的方式进行分割

以下是我的建议：

# Program that let's you find all numbers in any range defined by user
# that can be divided without any reminder by the number also defined by user

print('Find all numbers in range...')

while True:
    try:
        x = int(input('From: ')) # begining of the range
        y = int(input('.. to: ')) # end of the range
        z = int(input('.. that can be divided by: ')) # value of the number to divide by
    except ValueError: # in case of a nonint input
        print('You should enter a valid number!')
        continue
    numbers = range(x, y)
    if len(numbers) > 0 and z != 0:  #Check if the list is empty and if the divider is not null
        for number in numbers:
            if number % z == 0:
                print(number, [number / z])
    else:
        print("Invalid numbers passed")`

---

---

如果您希望程序在被零除事件时终止，最好按照@varad的建议引发一个异常。情况并非如此。我希望继续循环，直到用户输入正确的值gotcha。我的答案提供了您正在寻找的功能。如果您希望程序在被零除的事件中终止，最好按照@varad的建议引发一个异常。情况并非如此，我希望继续循环，直到用户输入正确的值gotcha。我的答案提供了您正在寻找的功能。我已经尝试了您建议的方案，它工作正常，但其他方式似乎都可以。。。什么都没有，程序以代码0终止，没有返回值…我已经尝试了您建议的方案，它工作正常，但它似乎以其他方式工作。。。没事，程序以代码0终止，不返回任何值…如果您想以异常方式解决它，为什么不简单地让

ZeroDivisionError

传播？对不起，我想我忘了提到我的母语不是英语。什么意思？@Varad谢谢你的建议，我运行了你的示例并终止了程序，这不是我的目标。@MichalFoc我想你不应该

引发异常。对不起，我误解了你的问题。如果是这样的话，你可以给出一个
print
语句，然后使用
break
从
for
循环中出来，返回
while
。如果你想解决这个问题，除了一个例外，为什么不简单地让
zeroditionerror
传播呢？对不起，我想我忘了提到我的母语不是英语。什么意思？@Varad谢谢你的建议，我运行了你的示例并终止了程序，这不是我的目标。@MichalFoc我想你不应该
引发异常。对不起，我误解了你的问题。如果是这样的话，你可以给出一个
print
语句，然后使用
break
从
for
循环中出来，转到
while
。谢谢Vinny，我喜欢你的想法，第1点肯定会像我用x>y测试它时一样实现，结果为0（虽然程序以代码0终止…），但是我认为有一个教育性的位是很好的，在这里你可以温和地通知/提醒用户你不应该除以0:）至于检查列表是否为空，我认为它是用除ValueError处理的。谢谢你的输入Hanks Vinny，我喜欢你的想法，第1点肯定会在我用x>y测试时实现，结果为0（虽然程序以代码0终止…），但是我觉得有一点教育意义很好，您可以温和地通知/提醒用户您不应该除以0:）至于检查列表是否为空，我认为它是用except ValueError处理的。谢谢你的意见