Python 用鼻子比较物体
我正在努力学习Python的艰苦练习49(),我需要比较两个不同的对象。这是我需要测试的代码:Python 用鼻子比较物体,python,unit-testing,nose,Python,Unit Testing,Nose,我正在努力学习Python的艰苦练习49(),我需要比较两个不同的对象。这是我需要测试的代码: class ParserError(Exception): pass class Sentence(object): def __init__(self, subject, verb, object): # remember we take ('noun','princess') tuples and convert them self.subject = subject
class ParserError(Exception):
pass
class Sentence(object):
def __init__(self, subject, verb, object):
# remember we take ('noun','princess') tuples and convert them
self.subject = subject[1]
self.verb = verb[1]
self.object = object[1]
def peek(word_list):
if word_list:
word = word_list[0]
return word[0]
else:
return None
def match(word_list, expecting):
if word_list:
word = word_list.pop(0) #Here it's returning 'noun' from the noun/princess tuple
if word[0] == expecting: #Here it's testing whether or not the new item in the 0 position ('noun' in this case) = expecting
return word
else:
return None
else:
return None
def skip(word_list, word_type):
while peek(word_list) == word_type:
match(word_list, word_type)
def parse_verb(word_list):
skip(word_list, 'stop')
if peek(word_list) == 'verb':
return match(word_list, 'verb')
else:
raise ParserError("Expected a verb next.")
def parse_object(word_list):
skip(word_list, 'stop')
next = peek(word_list)
if next == 'noun':
return match(word_list, 'noun')
if next == 'direction':
return match(word_list, 'direction')
else:
raise ParserError("Expected a noun or direction next.")
def parse_subject(word_list, subj):
verb = parse_verb(word_list)
obj = parse_object(word_list)
return Sentence(subj, verb, obj)
def parse_sentence(word_list):
skip(word_list, 'stop')
start = peek(word_list)
if start == 'noun':
subj = match(word_list, 'noun')
return parse_subject(word_list, subj)
elif start == 'verb':
# assume the subject is the player then
return parse_subject(word_list, ('noun', 'player'))
else:
raise ParserError("Must start with subject, object, or verb not: %s" % start)
我的问题是函数parse_-sensume
应该在这里创建一个句子对象。因此,我需要在测试代码中创建另一个句子对象,并确保它是相同的:
def test_parse_subject():
word_list = [('verb', 'kill'), ('direction', 'north')]
subj = ('noun', 'princess')
verb = ('verb', 'kill')
obj = ('direction', 'north')
obj_sent = Sentence(subj, verb, obj)
assert_equal(parser.parse_subject(word_list, subj), obj_sent)
但我一直收到这个回溯错误:
Traceback (most recent call last):
File "G:\Python27\lib\site-packages\nose\case.py", line 197, in runTest
self.test(*self.arg)
File "G:\Users\Charles\dropbox\programming\parsing_test\skeleton\tests\parser_tests.py", line 45, in test_parse_subjec
t
assert_equal(parser.parse_subject(word_list, subj), obj_sent)
AssertionError: <ex49.parser.Sentence object at 0x02651C50> != <ex49.parser.Sentence object at 0x02651C30>
回溯(最近一次呼叫最后一次):
runTest中的文件“G:\Python27\lib\site packages\nose\case.py”,第197行
自检(*self.arg)
文件“G:\Users\Charles\dropbox\programming\parsing\u test\skeleton\tests\parser\u tests.py”,第45行,在test\u parse\u subject中
T
assert_equal(parser.parse_subject(单词列表,subc),obj_sent)
断言者错误:!=
所以它不会返回相同的对象,但我很确定它们是一样的。我给了他们正确的论据。如果对象相同,如何确认?提前感谢这是失败的,因为您正在比较两个实例化的句子对象,而不是它们各自的属性 选中“”以查找可以比较属性的方法