Python 如果没有'；y'；或'；n'；

我对Python还不熟悉，并为此上了一堂课。 我正在制作一个“选择你自己的故事”游戏，用户在游戏中输入“y”或“n”以导致另一种情况。 以下是我的一部分：

print("Do you want to open the door")

if input() == "y":
    print("You opened the door. It is a mostly empty room but you spot something in the corner")

elif input() == "n":
    print("You decided not to enter the room, you move down the hallway")

if input() != "y" or "n":
    print("Please put y or n")

---

首先，您只需要一个

input（）

调用，并且需要将响应存储在变量中

然后，您需要一个循环，以便在他们给出错误答复时重复提示：

while True:
    response = input("Do you want to open the door?")

    if response == "y":
        print("You opened the door. It is a mostly empty room but you spot something in the corner")
        break
    elif response == "n":
        print("You decided not to enter the room, you move down the hallway")
        break
    print("Please put y or n")

然后，预见到在你的游戏中会有更多这样的提示，我们可以将其封装在一个返回True或False的函数中。（我也借此机会添加了下套管，以便

Y

或

Y

（或

N

/

N

）工作。）

---

要将输入与“y”和“n”进行比较，应设置一个变量来存储输入

print("Do you want to open the door")
x=input()
if x == "y":
    print("You opened the door. It is a mostly empty room but you spot something in the corner")

elif x == "n":
    print("You decided not to enter the room, you move down the hallway")

else:
    print("Please put y or n")

你的意思是什么？

print("Do you want to open the door")
x=input()
if x == "y":
    print("You opened the door. It is a mostly empty room but you spot something in the corner")

elif x == "n":
    print("You decided not to enter the room, you move down the hallway")

else:
    print("Please put y or n")