Python将变量输出到具有指定字符串的另一个变量

变量1具有：

 Server: Server1
 Power State: Faulty
 Power load: 120
 CPU State: Critical
 CPU Usage: 97%
 Mem State: Normal
 Mem Usage: 10%

我想要

variable2=Critical

这是cpu状态输出和cpu状态旁边的任何值

我不想打印到文件并对其进行grep

---

variable1输出是从命令输出中获取的，因为variable1是字符串数据类型

variable1 = " Server: Server1\n\
 Power State: Faulty\n\
 Power load: 120\n\
 CPU State: Critical\n\
 CPU Usage: 97%\n\
 Mem State: Normal\n\
 Mem Usage: 10%"
print variable1

match = re.search("CPU State:(.+)",variable1)
if(match):
        variable2 = match.group(1).strip()
        print variable2
else:   
        print "match not find"

---

您可以将每一行拆分为：，并将键、值放入字典。 与其提取所需的变量，不如将所有值存储在字典中。您将能够通过键访问任何值

def extract_values(string):
    string = string.strip()
    data = {}
    lines = string.split("\n")
    for line in lines:
        line = line.strip()
        key, value = line.split(":")
        data[key.strip()] = value.strip()
    return data

string = """
    Server: Server1
    Power State: Faulty
    Power load: 120
    CPU State: Critical
    CPU Usage: 97%
    Mem State: Normal
    Mem Usage: 10%
"""

data = extract_values(string)
print(data)
variable2 = data['CPU State']

数据将是：

>>> data
{'Power load': '120', 'Power State': 'Faulty', 'CPU Usage': '97%', 'Mem State': 'Normal', 'CPU State': 'Critical', 'Mem Usage': '10%', 'Server': 'Server1'}

---

假设variable1是一个字符串，最基本的非动态方法是

lines = variable1.splitlines()  # returns a list containing lines of variable1
for line in lines:
    if "CPU State" in line:
        # split the string by : and get the second item in list
        # and strip it to avoid any unwanted spaces before or after it
        variable2 = line.split(":")[1].strip()
print variable2

输出将是

Critical

---

variable1

是字典吗？类实例？还有别的吗？您有一些代码演示如何创建

variable1

吗？variable1不是字典。variable1输出来自命令output，您一定会设法将该字符串拆分成行，然后在冒号处拆分每一行：并找到以“CPU状态”开头的行？是的，我需要，CPU状态：CriticalGetting AttributeError:“非类型”对象没有属性“组”您能打印类型（变量1）吗？如果它不是字符串，它将无法工作