Python 如何在熊猫中组合groupby？

我有两个数据帧，我想使用Python连接groupby结果……我该怎么做

df1=pd.DataFrame({'Country':["US","CN","GB","US","DE","AU","CM","CU","CM"],'July Volume': [2541,3766,3071,1881,4653,1890,3203,1820,1411],
              'July Sales':[40264,40400,16135,41301,13757,45066,53709,42798,16184]})

df2=pd.DataFrame({'Country':["BA","CN","BE","US","AR","US","CM","CU","GB"],'Aug Volume':[4928,1665,4438,3241,4700,2304,2138,2692,4054],
              'Aug Sales':[18291,39776,41642,28364,21437,42000,56684,45179,23534]})

分组比df1

df1.groupby('Country').agg({'July Sales':['count','sum']})

分组比df2

df2.groupby('Country').agg({'Aug Sales':['count','sum']})

我的预期结果是：

因为实际数据非常大，有数百列，所以我不想先加入它们

有什么想法和想法吗？谢谢您的帮助。

您可以这样使用：

df1 = df1.groupby('Country').agg({'July Sales':['count','sum']})
df2 = df2.groupby('Country').agg({'Aug Sales':['count','sum']})

df = pd.concat([df1,df2],axis=1)

df将看起来像：

    July Sales         Aug Sales
         count    sum      count    sum
AR         NaN    NaN          1  21437
AU           1  45066        NaN    NaN
BA         NaN    NaN          1  18291
BE         NaN    NaN          1  41642
CM           2  69893          1  56684
CN           1  40400          1  39776
CU           1  42798          1  45179
DE           1  13757        NaN    NaN
GB           1  16135          1  23534
US           2  81565          2  70364

您可以这样使用：

df1 = df1.groupby('Country').agg({'July Sales':['count','sum']})
df2 = df2.groupby('Country').agg({'Aug Sales':['count','sum']})

df = pd.concat([df1,df2],axis=1)

df将看起来像：

    July Sales         Aug Sales
         count    sum      count    sum
AR         NaN    NaN          1  21437
AU           1  45066        NaN    NaN
BA         NaN    NaN          1  18291
BE         NaN    NaN          1  41642
CM           2  69893          1  56684
CN           1  40400          1  39776
CU           1  42798          1  45179
DE           1  13757        NaN    NaN
GB           1  16135          1  23534
US           2  81565          2  70364

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非常感谢。答案对我很有帮助，谢谢。答案对我有帮助。