Python多人游戏零和十字架

所以我在学校的时候用Python制作了一个单人游戏noughts和Cross

score=[[' ',' ',' '],[' ',' ',' '],[' ',' ',' ']]
global attempts
attempts = 0
from random import randint
from time import sleep

def grid(): #draws playing grid
    hideturtle()
    speed(0)
    pensize(0)
    penup()
    setpos(-200, -67)
    pendown()
    fd(400)
    penup()
    setpos(-200, 66)
    pendown()
    fd(400)
    penup()
    seth(90)
    setpos(-67, -200)
    pendown()
    fd(400)
    penup()
    setpos(66, -200)
    pendown()
    fd(400)

def drawShape(s, x, y): #draws shape in grid box x and y = coord, s = shape type
    hideturtle()
    speed(100)
    pensize(6)
    penup()
    if s == 'X': #draws 'X'
        pencolor("orange")
        setpos(-266+(133*x), -266+(133*y))
        pendown()
        seth(135)
        fd(50)
        rt(180)
        fd(100)
        rt(180)
        fd(50)
        rt(90)
        fd(50)
        rt(180)
        fd(100) 
    elif s == 'O': #draws 'O'
        pencolor("green")
        setpos(-266+(133*x), -266+(133*y)-40)
        seth(0)
        pendown()
        circle(40)



def ai(): #EXPERIMENTAL AI
    x=0
    y=0
    d='O'
    e='O'
    f='O'
    for i in range(3): #checks positions
        if i == 0:
            d=' '
        elif i == 1:
            d='O'
            e=' '
        elif i == 2:
            d='O'
            e='O'
            f=' '
        for c in range(3):
            if score[c][0] == d and score[c][1] == e and score[c][2] == f:
                x = c+1
                y = i+1
                print('v',c)
            elif score[c][0] == d and score[c][1] == e and score[c][2] == f:
                x = i=1
                y = c+1
                print('h',c)
        if score[0][0] == d and score[1][1] == e and score[2][2] == f:
            print('lr',i)
            x = i+1
            y = i+1
        elif score[0][2] == d and score[1][1] == e and score[2][0] == f:
            print('rl',i)
            x = i+1
            y = 4-i
    d='X'
    e='X'
    f='X'
    if x == 0 and y == 0: #checks oposition positions
        for i in range(3):
            if i == 0:
                d=' '
            elif i == 1:
                d='X'
                e=' '
            elif i == 2:
                d='X'
                e='X'
                f=' '
            for c in range(3): 
                if score[c][0] == d and score[c][1] == e and score[c][2] == f:
                    x = c+1
                    y = i+1
                    print('op v')
                elif score[c][0] == d and score[c][1] == e and score[c][2] == f:
                    x = i=1
                    y = c+1
                    print('op v')
            if score[0][0] == d and score[1][1] == e and score[2][2] == f:
                x = i+1
                y = i+1
                print('op bt')
            elif score[0][2] == d and score[1][1] == e and score[2][0] == f:
                x = i+1
                y = 4-i
                print('op tb')

    if x == 0 and y == 0: #if no playable positions uses random
        x = randint(1,3)
        y = randint(1,3)
    return x, y

def valid(u,x,y): #checks player move is valid
    global attempts
    if x > 3 or y > 3:
        print ('Coordinate must be between 1 & 3')
    elif x == '' or y == '':
        print("Enter something!")
    elif score[y-1][x-1] == ' ':
        score[y-1][x-1] = u
        drawShape(u, x, y)
        attempts +=1
        return True
    elif score[y-1][x-1] == u:
        print("You've already gone here! ")
        return False
    elif score[y-1][x-1] != u:
        print("The other player is here! ")
        return False


def userAgent(u): #makes AI or user prompts and sets array
    global attempts
    global a
    global b
    if u == 0:
        a, b = ai()
        score[b-1][a-1] = 'O'
        print("The computer is taking its turn...")
        print(a,b)
        sleep(1)
        drawShape('O', a, b)
        attempts +=1
    else:
        x = input("Player "+u+": enter x coordinate (1-3) ")
        y = input("Player "+u+": enter y coordinate (1-3) ")
        try:
            x = int(x)
            y = int(y)
        except ValueError:
            print("That's not a valid number!")
            userAgent(u)
        while True:
            if valid(u,x,y) == True:
                break
            x = input("Player "+u+": enter x coordinate (1-3) ")
            y = input("Player "+u+": enter y coordinate (1-3) ")
            try:
                x = int(x)
                y = int(y)
            except ValueError:
                print("That's not a valid number!")


def checkWin(n): #checks for a player win (3 in row) or stalemate
    for i in range(3):
        if score[i][0] == n and score[i][1] == n and score[i][2] == n:
            print("Player "+n+" won!")
            return True
        elif score[0][i] == n and score[1][i] == n and score[2][i] == n:
            print("Player "+n+" won!")
            return True
    if score[0][0] == n and score[1][1] == n and score[2][2] == n:
        print("Player "+n+" won!")
        return True
    elif score[0][2] == n and score[1][1] == n and score[2][0] == n:
        print("Player "+n+" won!")
        return True
    elif attempts == 9:
        print("Stalemate!")
        return True
    else:
        return False

def printGrid():
    print(score[2])
    print(score[1])
    print(score[0])

from turtle import *
grid()
p = input("Are you playing by yourself? (SINGLE PLAYER EXPERIMENTAL) (y/n) ")

while True: #runs game until player win
    if p == 'y':
        userAgent('X')
        printGrid()
        if checkWin('X') == True:
            break
        userAgent(0)
        printGrid()
        if checkWin('O') == True:
            break

    elif p == 'n':
        userAgent('X')

        if checkWin('X') == True:
            break
        userAgent('O')

        if checkWin('O') == True:
            break

    else:
        print("You need to type y or n - try again!")
        p = input("Are you playing by yourself? (SINGLE PLAYER EXPERIMENTAL) (y/n) ")

input('Press ENTER to exit')

忽略人工智能功能，它现在是永久性的实验（不起作用），但这不是问题所在

我在学校的开放日晚上帮忙，我想如果两个人可以在不同的电脑上玩，那会很酷。所以我会把服务器放在我的家用电脑上，进行端口转发，完成所有的逻辑工作，客户端只需接收输入，将它们发送到服务器上，然后由两个玩家移动。我知道HTTP POST/GET，但是我如何让服务器告诉客户端另一个玩家移动了？我研究了Twisted，它看起来不错，但我真的不理解类（我只是编程了一段时间）

这将在学校计算机上，因此我无法访问客户端的端口转发。理想情况下，我也会有一个IP白名单，这样只有我想要的计算机才能访问服务器

---

有人能帮我吗？我只需要了解服务器需要什么代码，以及客户端如何与之交互。谢谢：）

让两个客户端通过服务器交互的最简单方法是让两个客户端轮询服务器以获取更新。（您可以执行服务器端事件，但这对于您正在寻找的内容来说太复杂了）

但是，如果它们位于同一网络中，我建议在每个直接通信的设备上打开套接字服务器和客户端

我会这样做：

套接字服务器在两台计算机上都打开

无论谁启动游戏，都会打开一个套接字客户端，并将移动直接发送到服务器，然后重新打开一个套接字服务器

下一步，计算机将打开一个客户端，并将一个移动返回到服务器

这将删除运行服务器所需的所有代码

有关套接字，请参阅python手册。下面是服务器端和客户端的好例子

---

您可能想看看ZeroMQ

具体来说，你需要PyZMQ

它的设置很简单，您可以直接连接两台计算机。你可以在两者之间来回发送消息

当然要阅读文档，但您可能需要请求/回复模式。

您可以从

客户端可以使用Python的内置接口进行连接

---

稍后，如果愿意，您可以升级到使用twisted进行客户端连接。

服务器不必立即回复连接。通常你可以等到玩家1移动后再回复玩家2的连接。等等。是的，这是一个开放式的，有很多方法可以解决猫的皮肤问题。

"""The most basic chat protocol possible.

run me with twistd -y chatserver.py, and then connect with multiple
telnet clients to port 1025
"""

from twisted.protocols import basic



class MyChat(basic.LineReceiver):
    def connectionMade(self):
        print "Got new client!"
        self.factory.clients.append(self)

    def connectionLost(self, reason):
        print "Lost a client!"
        self.factory.clients.remove(self)

    def lineReceived(self, line):
        print "received", repr(line)
        for c in self.factory.clients:
            c.message(line)

    def message(self, message):
        self.transport.write(message + '\n')


from twisted.internet import protocol
from twisted.application import service, internet

factory = protocol.ServerFactory()
factory.protocol = MyChat
factory.clients = []

application = service.Application("chatserver")
internet.TCPServer(1025, factory).setServiceParent(application)