Python 将ListModelMixin与APIView组合以显示分页
我想在我的API中显示分页功能,我正在对多个序列化程序使用Python 将ListModelMixin与APIView组合以显示分页,python,django,pagination,django-rest-framework,Python,Django,Pagination,Django Rest Framework,我想在我的API中显示分页功能,我正在对多个序列化程序使用APIView。 我知道用ListView显示分页非常容易 我在某个地方看到,将ListModelMixin和APIView相结合是可行的,但如果我的代码如下所示: class ListModelMixin(object): def list(self, request, *args, **kwargs): queryset = self.filter_queryset(self.get_queryset())
APIView
。我知道用
ListView
显示分页非常容易我在某个地方看到,将
ListModelMixin
和APIView
相结合是可行的,但如果我的代码如下所示:
class ListModelMixin(object):
def list(self, request, *args, **kwargs):
queryset = self.filter_queryset(self.get_queryset())
page = self.paginate_queryset(queryset)
if page is not None:
serializer = self.get_serializer(page, many=True)
return self.get_paginated_response(serializer.data)
serializer = self.get_serializer(queryset, many=True)
return Response(serilaizer.data)
class ItemsAPIView(APIView):
permission_classes = (permissions.IsAuthenticated,)
pagination_class = api_settings.DEFAULT_PAGINATION_CLASS
def get(self, request, format=None):
"""
Return a list of all devices of this user.
"""
reply = {}
try:
products = BaseItem.objects.owned_items().filter(owner=request.user)
reply['data'] = OwnedItemSerializer(products, many=True).data
items = BaseItem.objects.dev_items().filter(owner=request.user)
reply['data'].extend(ItemSerializer(items, many=True).data)
except:
reply['data'] = []
return Response(reply, status.HTTP_200_OK)
我如何组合它们,以便获得分页结果提前谢谢 首先,你目前正在做的事情太复杂了,没有理由 为了实现“可分页”查询集,最好在简单的筛选器组合中更改
owned_items()
和dev_items()
,而不是使用模型方法。举例说明:
products = BaseItem.objects.filter(owner=request.user, owned=True)
而不是
products = BaseItem.objects.owned_items().filter(owner=request.user)
这样,您就可以生成一个更容易分页的queryset:
user_items = BaseItem.objects.filter(
Q(owner=request.user, owned=True) |
Q(owner=request.user, dev=True)
)
注1:如果您愿意,可以进一步简化,但这超出了您的问题范围。值得思考的是,请查看以下内容:
user_items = BaseItem.objects.filter(owner=request.user).distinct()
注意2:您应该为单个模型使用单个序列化程序,因为您所做的工作增加了复杂性,但没有带来任何好处(高风险低回报情况)
在上述情况下,假设: 这里有一些方法可以实现您的目标:
.list()
方法:
from rest_framework import mixins, generics
class ItemsAPIView(mixins.ListModelMixin, generics.GenericAPIView,):
permission_classes = (permissions.IsAuthenticated,)
pagination_class = api_settings.DEFAULT_PAGINATION_CLASS
serializer_class = OwnedItemSerializer
# You can define .get in here if you really need it.
# You can also override .list to add specific functionality
APIView
,则可以保留get
方法并为其提供分页,如下所述:
虽然我了解了您尝试执行的操作要点,但我建议
ItemAPIView
不要尝试以您目前的方式查询数据。视图应该提供queryset
,其余的应该由序列化程序完成。如果您可以提供您正在寻找的那种o/p以及序列化器
定义,则可以发布一个明确的解决方案。我正在寻找的输出只是分页功能。如果我使用/api/v1/items?page=1,我每页应该有10个项目。使用的两个序列化程序是一个用于自有项目,另一个用于开发项目。@ShikharChauhan您了解两个序列化程序在我的情况下的用法吗?不,没有序列化程序代码很难判断。
class ItemsAPIView(APIView):
permission_classes = (permissions.IsAuthenticated,)
pagination_class = api_settings.DEFAULT_PAGINATION_CLASS
serializer_class = MyNewUnifiedSerializerClass
def get(self, request):
user_items = BaseItem.objects.filter(
owner=request.user
).distinct()
page = self.paginate_queryset(user_items)
if page is not None:
serializer = self.serializer_class(page, many=True)
return self.get_paginated_response(serializer.data)
serializer = self.get_serializer(user_items, many=True)
return Response(serializer.data)
# Now add the pagination handlers taken from
# django-rest-framework/rest_framework/generics.py
@property
def paginator(self):
"""
The paginator instance associated with the view, or `None`.
"""
if not hasattr(self, '_paginator'):
if self.pagination_class is None:
self._paginator = None
else:
self._paginator = self.pagination_class()
return self._paginator
def paginate_queryset(self, queryset):
"""
Return a single page of results,
or `None` if pagination is disabled.
"""
if self.paginator is None:
return None
return self.paginator.paginate_queryset(
queryset,
self.request,
view=self
)
def get_paginated_response(self, data):
"""
Return a paginated style `Response` object
for the given output data.
"""
assert self.paginator is not None
return self.paginator.get_paginated_response(data)