如何在python中读取带符号的16位TIFF？

我使用OpenCV的imread（）读取TIFF。但价值观和我已经知道的不一样。此TIFF是有符号16位，它有负值。使用imread（）的值范围为0~65535，它是无符号16位

import cv2 as cv

img = cv.imread("MYD_20140102.tif",2)
print img
print img.dtype 
print img.shape
print img.min()
print img.max()

cv.namedWindow("Image")
cv.imshow("Image",img)
cv.waitKey(0)
cv.destroyAllWindows()


output:
img=[[55537 55537 55537 ... 55537 55537 55537]
 [55537 55537 55537 ... 55537 55537 55537]
 [55537 55537 55537 ... 55537 55537 55537]
 ...
 [55537 55537 55537 ... 55537 55537 55537]
 [55537 55537 55537 ... 55537 55537 55537]
 [55537 55537 55537 ... 55537 55537 55537]]
type=uint16
shape=(2318, 2296)
imgMin=0
imgMAX=65535

库文件（）正是您想要的。 以下是创建int16 numpy阵列，将其保存在磁盘上，然后重新加载的示例：

import tifffile
import numpy as np

# random array of numbers between -5 and 5
a = np.asarray(np.random.rand(8, 8)*10-5, dtype=np.int16)
# save array to disk and display its content
tifffile.imsave("test.tiff", a)
print(str(a) + "\n")
# load the array back from the disk and display its content too
b = tifffile.imread("test.tiff")
print(b)

输出：

a=[[ 1 -1 -3  2  3 -1  4  0]
   [ 2 -2  2  0 -1  0  3 -4]
   [ 0 -4  3  2 -4 -2  0 -3]
   [ 0 -1  0 -2  0  3 -3  1]
   [ 0 -4  3  1 -1  3  2  3]
   [-3  4  4  3 -3  1 -3 -2]
   [ 4  0 -4 -2  1 -3  3 -3]
   [ 4  0  4  2  3  1 -2 -4]]

b=[[ 1 -1 -3  2  3 -1  4  0]
   [ 2 -2  2  0 -1  0  3 -4]
   [ 0 -4  3  2 -4 -2  0 -3]
   [ 0 -1  0 -2  0  3 -3  1]
   [ 0 -4  3  1 -1  3  2  3]
   [-3  4  4  3 -3  1 -3 -2]
   [ 4  0 -4 -2  1 -3  3 -3]
   [ 4  0  4  2  3  1 -2 -4]]