Python 为什么打印语句是'；其他'；条款仍在执行？

我是编程新手，这是我的代码。当我输入'banana'时，结果是'banana is fruit'，但它也会从'else'子句中打印'unknown'。为什么?

product = str(input("Chose Product : "))

if product == "banana" or product == "apple" or product == "kiwi" or product == "lemon":
    print(f"{product} is fruite")
if product == "pepper" or product == "tomato" or product == "cucumber" or product == "carrot":
    print(f"{product} is vegetable")

else:
    print("unknown")

---

在第二种情况下使用elif而不是if。

尝试以下方法：

product = str(input("Chose Product : "))

if product == "banana" or product == "apple" or product == "kiwi" or product == "lemon":
    print(f"{product} is fruite")
elif product == "pepper" or product == "tomato" or product == "cucumber" or product == "carrot":
    print(f"{product} is vegetable")
else:
    print("unknown")

elif

将else链接到第一个if。 在您的代码中，else仅在第二个if不为True时执行，而第一个if单独工作。

试试看

product = str(input("Chose Product : "))


if product == "banana" or product == "apple" or product == "kiwi" or product == "lemon":
    print(f"{product} is fruite")
elif product == "pepper" or product == "tomato" or product == "cucumber" or product == "carrot":
    print(f"{product} is vegetable")
else:
    print("unknown")

---

如果不使用elif链接if，则如果if高于else为false，则else将起作用

此代码有效

product = str(input("Chose Product : "))
if product == "banana" or product == "apple" or product == "kiwi" or product == "lemon":

    print(f"{product} is fruite")
elif product == "pepper" or product == "tomato" or product == "cucumber" or product == "carrot":
    print(f"{product} is vegetable")

else:
    print("unknown")

---

只需将中间的if替换为elif，以保持链

将第二个

if

设置为

elif

，使其成为相同条件的一部分，而不是一个全新的条件。另外，在

输入

调用周围不需要

str

，它已经返回了一个

str

：）您需要使用

elif

，因为您使用的是两个

If

块，所以在从第一个块获得结果后，它会检查第二个块，它不在那里，所以

其他
部分会被打印出来，如果产品在（“香蕉”、“苹果”、“猕猴桃”、“柠檬”）中，那么
操作会更容易一些：
而不是所有的
或
s…天哪，我太笨了，谢谢。请考虑确认答案。