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Python 选择范围内矩阵的值_Python_Numpy_Matrix - Fatal编程技术网

Python 选择范围内矩阵的值

Python 选择范围内矩阵的值,python,numpy,matrix,Python,Numpy,Matrix,我有下面的代码来绘制圆(通过将矩阵的0改为1)。我遇到一些问题,代码试图在矩阵的列/行之外绘制点,并导致错误 def renderCircle(Nx,Ny,radius): #function for drawing circles at x,y with radius r x = np.round(radius*x_circ+Nx).astype(int) y = np.round(radius*y_circ+Ny).astype(int) for x in x: fo

我有下面的代码来绘制圆(通过将矩阵的0改为1)。我遇到一些问题,代码试图在矩阵的列/行之外绘制点,并导致错误

def renderCircle(Nx,Ny,radius): #function for drawing circles at x,y with radius r
  x = np.round(radius*x_circ+Nx).astype(int)
  y = np.round(radius*y_circ+Ny).astype(int)
  for x in x:
      for y in y:
          if x>0 and x<1024:
              if y>0 and y<1024:
                  S[x,y] = 1
def renderCircle(Nx,Ny,半径):#用于在x,y处绘制半径为r的圆的函数
x=np.圆形(半径*x_圆周+Nx).aType(整数)
y=np.圆形(半径*y_circ+Ny).aType(整数)
对于x中的x:
对于y中的y:
如果x>0,x0和y