无法停止Python中的函数
我对我创建的函数有问题,它不会停止,有人能告诉我我做错了什么吗无法停止Python中的函数,python,function,Python,Function,我对我创建的函数有问题,它不会停止,有人能告诉我我做错了什么吗 import random words = ["monitor", "mouse", "CPU", "keyboard"] attempts = [] randomWord = random.choice(words) noChar = len(randomWord) print randomWord , noChar print "Hello, Welcome to the game of Hangman. You ha
import random
words = ["monitor", "mouse", "CPU", "keyboard"]
attempts = []
randomWord = random.choice(words)
noChar = len(randomWord)
print randomWord , noChar
print "Hello, Welcome to the game of Hangman. You have to guess the given word. The first word has", noChar, " letters."
def game():
guess = raw_input ("Please choose letter")
attempts.append(guess)
print (attempts)
if guess in randomWord:
print "You have guessed the letter"
else:
print "Please try again"
return()
chance = raw_input ("Have a guess")
while chance!= randomWord:
game()
您要求猜测的输入需要在
游戏
功能内或每次完成时触发多次
在游戏开始时,您只要求获得机会。除非玩家立即猜出单词,否则不会触发胜利条件
像这样的东西可以解决它:
def game():
guess = input ("Please choose letter")
attempts.append(guess)
print (attempts)
if guess in randomWord:
print ("You have guessed the letter" )
else:
print ("Please try again")
while True:
game()
chance = input ("Have a guess")
if chance == randomWord:
print('You win!')
break
额外提示:要按顺序打印所有成功的猜测,即按隐藏单词中的顺序打印,您可以执行以下操作:
def game():
guess = input ("Please choose letter")
if guess in randomWord:
success.append(guess)
attempts.append(guess)
print (attempts)
print(sorted(success, key=randomWord.index))
if guess in randomWord:
print ("You have guessed the letter" )
else:
print ("Please try again")
将输出:
Hello, Welcome to the game of Hangman. You have to guess the given word. The first word has 7 letters.
Please choose letterm
[]
['m']
You have guessed the letter
Have a guesst
Please choose lettert
[]
['m', 't']
You have guessed the letter
Have a guess
Please choose lettero
[]
['m', 'o', 't']
You have guessed the letter
Have a guess
这允许玩家查看正确字母的顺序。您希望它什么时候停止?您使用的是哪个版本的Python?我不确定3.x,但我知道在2.xreturn
中有一个语句(不应该有括号)