Python 如何提取xml文件的一部分

我有一个很大的xml文件，看起来像下面的那个。基本上，我想提取xml文件的一部分，例如有这样的

“

”

这意味着在解析I wnat以提取此部分后：

<SubNetwork networkType = "WRAN" userLabel="AHPTUR14">
            <ManagedElement sourceType = "CELLO">
                <ManagedElementId string = "rbs064841"/>
                <primaryType type = "RBS"/>
                <managedElementType types = ""/>
                <associatedSite string = "Site=site06484"/>
                <nodeVersion string = "W12B"/>
                <platformVersion string = "Cello 12.2"/>
                <swVersion string = ""/>
                <vendorName string = "ERICSSON"/>
                <userDefinedState string = ""/>
                <managedServiceAvailability int = "1"/>
                <isManaged boolean = "true"/>
                <neMIMVersion string = "vS.1.150"/>
                <connectionStatus string = "ON"/>
            </ManagedElement>
        </SubNetwork>

因此，通过

ManagedElementId

在大xml文件中进行搜索，找到时提取找到它的部分，即从

到

。 我知道如何从xml文件中提取数据，但我不知道如何提取xml.file的一部分。我正在使用python元素树。

---

任何建议都会很有帮助。

使用

查找
和
路径
，然后获取相对的父节点，如下所示：

s = '''<Model version = "1" importVersion = "12.2">
        <Create>
            <SubNetwork networkType = "WRAN" userLabel="AHPTUR14">
                <ManagedElement sourceType = "CELLO">
                    <ManagedElementId string = "rbs064841"/>
                    <primaryType type = "RBS"/>
                    <managedElementType types = ""/>
                    <associatedSite string = "Site=site06484"/>
                    <nodeVersion string = "W12B"/>
                    <platformVersion string = "Cello 12.2"/>
                    <swVersion string = ""/>
                    <vendorName string = "ERICSSON"/>
                    <userDefinedState string = ""/>
                    <managedServiceAvailability int = "1"/>
                    <isManaged boolean = "true"/>
                    <neMIMVersion string = "vS.1.150"/>
                    <connectionStatus string = "ON"/>
                </ManagedElement>
            </SubNetwork>
             <SubNetwork networkType = "WRAN" userLabel = "AHPT78">
                <ManagedElement sourceType = "CELLO">
                    <ManagedElementId string = "rbs04798"/>
                    <primaryType type = "RBS"/>
                    <managedElementType types = ""/>
                    <associatedSite string = "Site=site06484"/>
                    <nodeVersion string = "W12B"/>
                    <platformVersion string = "Cello 12.2"/>
                    <swVersion string = ""/>
                    <vendorName string = "ERICSSON"/>
                    <userDefinedState string = ""/>
                    <managedServiceAvailability int = "1"/>
                    <isManaged boolean = "true"/>
                    <neMIMVersion string = "vS.1.150"/>
                    <connectionStatus string = "ON"/>
                </ManagedElement>
            </SubNetwork>
            <SubNetwork networkType = "WRAN" userLabel = "AHPT4">
                <ManagedElement sourceType = "CELLO">
                    <ManagedElementId string = "rbs04456"/>
                    <primaryType type = "RBS"/>
                    <managedElementType types = ""/>
                    <associatedSite string = "Site=site06484"/>
                    <nodeVersion string = "W12B"/>
                    <platformVersion string = "Cello 12.2"/>
                    <swVersion string = ""/>
                    <vendorName string = "ERICSSON"/>
                    <userDefinedState string = ""/>
                    <managedServiceAvailability int = "1"/>
                    <isManaged boolean = "true"/>
                    <neMIMVersion string = "vS.1.150"/>
                    <connectionStatus string = "ON"/>
                </ManagedElement>
            </SubNetwork>
        </Create>
    </Model>'''


希望这有帮助。
我使用的是python 2.6，没有安装lxml，由于管理员权限，我无法安装它。通过xml.etree还有其他方法吗？@user3319356，最后一个代码块正好用于
xml
模块。让我整理一下答案，这样你就知道该怎么做了。谢谢，现在没事了。我需要解析大文件，所以我想用open（r“C:\\Users\\etihkru\\Desktop\\big.xml“，'rt'）作为f:tree=ET.parse（f）来解析文件，而不是变量“s”，但这样不行吗？tree1=ET.fromstring（tree）@user3319356，请参阅我的更新。只需使用
root=ET.parse（…）
，然后使用
tree=root.getroot（）
s = '''<Model version = "1" importVersion = "12.2">
        <Create>
            <SubNetwork networkType = "WRAN" userLabel="AHPTUR14">
                <ManagedElement sourceType = "CELLO">
                    <ManagedElementId string = "rbs064841"/>
                    <primaryType type = "RBS"/>
                    <managedElementType types = ""/>
                    <associatedSite string = "Site=site06484"/>
                    <nodeVersion string = "W12B"/>
                    <platformVersion string = "Cello 12.2"/>
                    <swVersion string = ""/>
                    <vendorName string = "ERICSSON"/>
                    <userDefinedState string = ""/>
                    <managedServiceAvailability int = "1"/>
                    <isManaged boolean = "true"/>
                    <neMIMVersion string = "vS.1.150"/>
                    <connectionStatus string = "ON"/>
                </ManagedElement>
            </SubNetwork>
             <SubNetwork networkType = "WRAN" userLabel = "AHPT78">
                <ManagedElement sourceType = "CELLO">
                    <ManagedElementId string = "rbs04798"/>
                    <primaryType type = "RBS"/>
                    <managedElementType types = ""/>
                    <associatedSite string = "Site=site06484"/>
                    <nodeVersion string = "W12B"/>
                    <platformVersion string = "Cello 12.2"/>
                    <swVersion string = ""/>
                    <vendorName string = "ERICSSON"/>
                    <userDefinedState string = ""/>
                    <managedServiceAvailability int = "1"/>
                    <isManaged boolean = "true"/>
                    <neMIMVersion string = "vS.1.150"/>
                    <connectionStatus string = "ON"/>
                </ManagedElement>
            </SubNetwork>
            <SubNetwork networkType = "WRAN" userLabel = "AHPT4">
                <ManagedElement sourceType = "CELLO">
                    <ManagedElementId string = "rbs04456"/>
                    <primaryType type = "RBS"/>
                    <managedElementType types = ""/>
                    <associatedSite string = "Site=site06484"/>
                    <nodeVersion string = "W12B"/>
                    <platformVersion string = "Cello 12.2"/>
                    <swVersion string = ""/>
                    <vendorName string = "ERICSSON"/>
                    <userDefinedState string = ""/>
                    <managedServiceAvailability int = "1"/>
                    <isManaged boolean = "true"/>
                    <neMIMVersion string = "vS.1.150"/>
                    <connectionStatus string = "ON"/>
                </ManagedElement>
            </SubNetwork>
        </Create>
    </Model>'''

# I'd prefer lxml, but you need to work on xml module...
import xml.etree.ElementTree as ET
tree = ET.fromstring(s)

# since the SubNetwork node you're interested is the parent of parent of ManagedElementId
node = tree.find('.//ManagedElementId[@string="rbs064841"]/../../../')

print ET.tostring(node)
<SubNetwork networkType="WRAN" userLabel="AHPTUR14">
                <ManagedElement sourceType="CELLO">
                    <ManagedElementId string="rbs064841"/>
                    <primaryType type="RBS"/>
                    <managedElementType types=""/>
                    <associatedSite string="Site=site06484"/>
                    <nodeVersion string="W12B"/>
                    <platformVersion string="Cello 12.2"/>
                    <swVersion string=""/>
                    <vendorName string="ERICSSON"/>
                    <userDefinedState string=""/>
                    <managedServiceAvailability int="1"/>
                    <isManaged boolean="true"/>
                    <neMIMVersion string="vS.1.150"/>
                    <connectionStatus string="ON"/>
                </ManagedElement>
            </SubNetwork>

root = ET.parse('file.xml')
tree = root.getroot()
...