解析嵌套Python dict
我有一个嵌套字典,我正试图解析它,但似乎不知道如何访问第三级项。谢谢你的帮助 这是我的字典解析嵌套Python dict,python,json,dictionary,nested,Python,Json,Dictionary,Nested,我有一个嵌套字典,我正试图解析它,但似乎不知道如何访问第三级项。谢谢你的帮助 这是我的字典 { "FunctionName": "RDSInstanctStart", "LastModified": "2018-03-24T07:19:56.792+0000", "MemorySize": 128, "Environment": { "Variables": { "DBInstanceName": "test1234"
{
"FunctionName": "RDSInstanctStart",
"LastModified": "2018-03-24T07:19:56.792+0000",
"MemorySize": 128,
"Environment": {
"Variables": {
"DBInstanceName": "test1234"
}
},
"Version": "$LATEST",
"Role": "arn:aws:iam::xxxxxxx:role/lambda-start-RDS",
"Timeout": 3,
"Runtime": "python2.7",
"TracingConfig": {
"Mode": "PassThrough"
},
"CodeSha256": "tBdB+UDA9qlONGb8dgruKc6Gc82gvYLQwdq432Z0118=",
"Description": "",
"VpcConfig": {
"SubnetIds": [],
"SecurityGroupIds": []
},
"CodeSize": 417,
"FunctionArn": "arn:aws:lambda:us-east-1:xxxxxxxx:function:RDSInstanctStart",
"Handler": "lambda_function.lambda_handler"
}
我正在尝试访问关键变量的值
以下是我目前的代码:
try:
for evnt in funcResponse['Environment']['Variables']['DBInstanceName']:
print (evnt[0])
except ClientError as e:
print(e)
我得到的结果是
t
e
s
t
1
2
3
4
如果我没有给出envt变量的索引,我会得到一个类型错误。funcResponse['Environment']['Variables']['DBInstanceName']是一个字符串,但您正在循环它。字符串是单个字符的序列
如果在test1234中为character:printcharacter[0]执行了以下操作,您将得到相同的结果,并且您也可以删除[0]索引,因为character就像字符串一样,只包含一个字符
不要循环,只需打印:
evnt = funcResponse['Environment']['Variables']['DBInstanceName']
print(evnt)
如果要打印所有环境变量,则必须循环funcResponse['environment']['variables']字典中的项:
for name, value in funcResponse['Environment']['Variables'].items():
print(name, value, sep=': ')
无论如何,funcResponse['Environment']['Variables']只是一个字典。将['DBInstanceName']添加到末尾将为'DBInstanceName'键提供值。谢谢Martijn。我现在明白了。还感谢您为所有环境变量编写循环代码段。在某一点上,我也会这样做。作为一方,您可能对类似或其竞争对手的东西感兴趣,将嵌套集合视为具有复杂路径的平面集合,如键的“Environment/Variables/DBInstanceName”。