Python 如何在字典中显示多个项目？

我有一个程序，它有一个搜索选项，如果鸡肉或鸡肉在库存中，它只需输入chi（不区分大小写）即可调出物品。问题是如何使函数返回包含chi的所有项

例如，如果我有鸡、鸡、鸡和鸡的存货，我应该能够输入chi，它应该打印出每个项目的所有信息

受影响的代码（非完整程序）：

我该如何解决这个问题

用于测试的完整程序代码：

import os
import json

class Inventory:
    def __init__(self):
        #AT LAUNCH GROUPS AND LOADING FUNCTION
        self.items = {}
        self.load()

    def remove(self, ID):
        #REMOVING ITEMS FOR LISTS AND OUTPUT DOCUMENT
        del self.items[str(ID)]
        self.save()

    def add(self, ID, name, qty):
        #ADDING ITEMS FOR LISTS AND OUTPUT DOCUMENT
        self.items[str(ID)] = {"name": name, "qty": qty}
        self.save()

    def update(self, ID, update):
        #UPDATING ITEMS FOR LISTS AND OUTPUT DOCUMENT
        self.items[str(ID)]["qty"] += update
        self.save()

    def search(self, query):
        #SEARCHING DATA BASED ON CLOSEST CHARACTER MATCH - NOT CASE SENSITIVE
        output = []
        for id in self.items:
            if str(query) == id or self.items[id]['name'].lower().startswith(str(query).lower()):
                output.append((id, self.items[id]['name'], self.items[id]['qty']))
        if output: return output
        else: return None

    def __str__(self):
        #FORMATTING
        out = ""
        for id, d in self.items.items():
            out += f"ID Number : {id} \nItem Name : {d['name']}\nQuantity : {d['qty']}\n"
            out += "----------\n"
        return out
    
    def save(self):
        #WHERE TO SAVE TO
        with open('data.txt','w') as outfile:
           json.dump(self.items, outfile)

    def load(self):
        #WHERE TO PUT DATA FROM WHEN RELAUNCHING PROGRAM
        try:
            with open('data.txt','r') as json_file:
               self.items = json.load(json_file)
        except:
            print("Can't load old inventory, starting fresh")
            self.items = {}


def menuDisplay():
    #MENU FOR PROGRAM 
    """Display the menu"""
    print('=============================')
    print('= Inventory Management Menu =')
    print('=============================')
    print('(1) Add New Item to Inventory')
    print('(2) Remove Item from Inventory')
    print('(3) Update Inventory')
    print('(4) Search Item in Inventory')
    print('(5) Print Inventory Report')
    print('(99) Quit')


def add_one_item(inventory):
    #ADDING PROMPT AND ERROR CHECKING
    print('Adding Inventory')
    print('================')
    while True:
        try:
            new_ID = int(input("Enter an ID number for the item: "))
            if inventory.search(new_ID):
                print("ID number is taken, please enter a different ID number")
                continue
            new_name = input('Enter the name of the item: ')
            new_qty = int(input("Enter the quantity of the item: "))
            inventory.add(new_ID, new_name, new_qty)
            break
        except Exception as e:
            print("Invalid choice! try again! " + str(e))
            print()


def remove_one_item(inventory):
    #REMOVING PROMPT AND ERROR CHECKING
    print('Removing Inventory')
    print('==================')
    while True:
        try:
            removing = int(input("Enter the item's ID number to remove from inventory: "))
            if inventory.search(removing):
                inventory.remove(removing)
            else:
                print("Item not in inventory")
                continue
            break
        except Exception as e:
            print("Invalid choice! try again! " + str(e))
            print()


def ask_exit_or_continue():
    #OPTION TO CONTINUE OR QUITE PROGRAM
    return int(input('Enter 98 to continue or 99 to exit: '))


def update_inventory(inventory):
    #UPDATING PROMPT AND ERROR CHECKING
    print('Updating Inventory')
    print('==================')
    while True:
        try:
            ID = int(input("Enter the item's ID number to update: "))
            if inventory.search(ID):
                update = int(input("Enter the updated quantity. Enter 5 for additional or -5 for less: "))
                inventory.update(ID, update)
            else:
                print("ID number is not in the system, please enter a different ID number")
                continue
            break
        except Exception as e:
            print("Invalid choice! try again! " + str(e))
            print()

def search_inventory(inventory):
    #SEARCHING PROMPT AND ERROR CHECKING
    print('Searching Inventory')
    print('===================')
    while True:
        try:
            search = input("Enter the name of the item: ")
            result = inventory.search(search)
            if result is None:
                print("Item not in inventory")
                continue
            else:
                for found in result:
                    ID, name, qty = found
                    print('ID Number: ', ID)
                    print('Item:     ', name)
                    print('Quantity: ', qty)
                    print('----------')
            break
        except Exception as e:
            print("Invalid choice! try again! " + str(e))
            print()


def print_inventory(inventory):
    #PRINT CURRENT LIST OF ITEMS IN INVENTORY
    print('Current Inventory')
    print('=================')
    print(inventory)


def main():
    #PROGRAM RUNNING COMMAND AND ERROR CHECKING
    inventory = Inventory()
    while True:
        try:
            menuDisplay()
            CHOICE = int(input("Enter choice: "))
            if CHOICE in [1, 2, 3, 4, 5]:
                if CHOICE == 1:
                    add_one_item(inventory)
                elif CHOICE == 2:
                    remove_one_item(inventory)
                elif CHOICE == 3:
                    update_inventory(inventory)
                elif CHOICE == 4:
                    search_inventory(inventory)
                elif CHOICE == 5:
                    print_inventory(inventory)
                exit_choice = ask_exit_or_continue()
                if exit_choice == 99:
                    exit()
            elif CHOICE == 99:
                exit()
        except Exception as e:
            print("Invalid choice! try again!"+str(e))
            print()

        # If the user pick an invalid choice,
        # the program will come to here and
        # then loop back.


main()

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代码返回第一个匹配项。此搜索返回所有匹配项

    def search(self, query):
    """ Search items for all matching id's in query.
    """
    output = [id for id in self.items if str(query).upper() in id.upper()]
    return output if output != [] else None

作为一个独立的演示，我构建了一个包含3个项目的数据库和一个搜索方法的类

对于搜索方法，我在列表中使用id.upper（）中的if str（query）.upper（）

Db类：
定义初始化（自）：
self.items={
'Picture1'：{'name'：'name1'，'qty'：1}，
'Picture2'：{'name'：'name2'，'qty'：2}，
'Picture3'：{'name'：'name3'，'qty'：3}
def搜索（自我，查询）：
return[（id，self.items[id]['name']，self.items[id]['qty']）
如果id.upper（）中的str（query.upper（）），则表示self.items中的id
db=db（）
db.search（'pic'）
db.search（'ure2'）

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如果你觉得这个问题无法解释，也许我答错了。您应该尝试更好地解释。

您能更新您的答案以使用我提供的程序代码吗？答案已更新。第一个代码块可以复制并粘贴到您的代码中。您的错误是在尚未获取所有信息时使用return。请查看我的帖子以获得进一步的解释。我认为这是正确的，但我一直得到一个关于if输出的无效语法：@GeorgeDavidson请向我显示错误消息，并将id变量更改为其他内容，因为它是if输出中的内置函数名：“：”突出显示橙色。没有特殊的错误消息。@GeorgeDavidson我已经编辑了这篇文章，不要复制并粘贴到你的py文件中，因为缩进，请重写它。上面写着“：”仍然突出显示橙色

    def search(self, query):
    """ Search items for all matching id's in query.
    """
    output = [id for id in self.items if str(query).upper() in id.upper()]
    return output if output != [] else None

def search(self, query):
        #SEARCHING DATA BASED ON CLOSEST CHARACTER MATCH - NOT CASE SENSITIVE
        output = []
        for id in self.items:
            if str(query) == id or self.items[id]['name'].lower().startswith(str(query).lower()):
                output.append((id, self.items[id]['name'], self.items[id]['qty']))
        if output:
            return output
        else: 
            return None