Python 巨蟒3：石头、布、剪刀发行

我正在做一个石头、布、剪刀的游戏来做编程作业，我遇到了一个小麻烦。假设该程序由用户运行，用户选择4个选项中的1个，1）石头，2）布，3）剪刀和4）退出。一旦玩家选择了一个选项，将显示计算机选项，并宣布获胜者，程序将询问您是否想玩另一个游戏。如果选择y，则返回主菜单选择另一个选项，其他任何选项都将显示赢得、输掉的比赛数量以及平局结束的比赛数量。如果玩家选择4，程序应显示“退出程序…”，并显示游戏结果

以下是我的问题：

第一次选择后，将显示赢家，程序将返回主菜单。如果您进行第二次选择，它将通知您计算机选择了什么，然后询问您是否愿意再次播放。Y将带您回到主菜单，计算机选择将永远不会改变，无论您选择什么，游戏将始终以与第一场游戏相同的结果结束。如果您选择不再玩游戏，则会显示赢得、输掉和平局的游戏数量（这似乎功能正常）

退出选项会将您带回主菜单，而不是显示游戏结果。我不知道该把if语句放在哪里

如果您对这些问题有任何帮助，我们将不胜感激

多谢各位

#import module
import random

def main():
    #create a variable to control the loop
    play_again = 'y'

    #create a counter for tied games, computer games and player games
    tied_games = 0
    computer_games = 0
    player_games = 0

    #display opening message
    print("Let's play rock, paper scissors!") 

    computer_choice = process_computer_choice()

    player_choice = process_player_choice()

    winner = determine_winner(player_choice, computer_choice)

    #setup while loop for playing multiple games
    while play_again == 'y' or play_again == 'Y':

        process_computer_choice()

        process_player_choice()

        #use a if else statement to print the computers choice
        if computer_choice == 1:
            print('computer chooses rock.')

        elif computer_choice == 2:
            print('computer chooses paper.')

        else:
            print('computer chooses scissors.')

            #call the determine winner function    
            determine_winner(player_choice, computer_choice)

        #check who won the game and add 1 to the correct counter
        if winner == 'computer':
            computer_games += 1

        elif winner == 'player':
            player_games += 1

        else:
            tied_games += 1

        #ask the user if they would like to play again    
        play_again = input('would you like to play again? (enter y for yes): ')

    #display number of games that were won by the computer, the player and that were tied
    print()
    print('there was', tied_games, 'tied games.')
    print('the player won', player_games, 'games.')
    print('The computer won', computer_games,'games.')

#define the process computer function
def process_computer_choice():

    #setup computer to select random integer between 1 and 3
    choice1 = random.randint(1, 3)

    #return the computers choice
    return choice1

#define the process player function
def process_player_choice():

    #add input for players choice
    print()
    print('        MENU')
    print('1) Rock!')
    print('2) Paper!')
    print('3) Scissors!')
    print('4) Quit')
    print()

    player_choice = int(input('Please make a selection:  '))

    #add if statement for quit option
    if player_choice == 4:
        print('Exiting program....')

   #validate if the user enters a correct selection
    while player_choice != 1 and player_choice != 2 and player_choice != 3 and player_choice != 4:

        #print a error message if the wrong selection is entered
        print('Error! Please enter a correct selection.')

        player_choice = int(input('Please make a selection: '))

    #return the players choice
    return player_choice

#define the determine winner function
def determine_winner(player_choice, computer_choice):

    #setup if else statements for each of the 3 computer selections
    if computer_choice == 1:
        if player_choice == 2:
            print('Paper wraps rock. You win!')
            winner = 'player'

        elif player_choice == 3:
            print('Rock smashes scissors. The computer wins!')
            winner = 'computer'

        else:
            print('The game is tied. Try again.')
            winner = 'tied'

    if computer_choice == 2:
        if player_choice == 1:
            print('Paper wraps rock. The computer wins!')
            winner = 'computer'

        elif player_choice == 3:
            print('Scissors cut paper. You win!')
            winner = 'player'

        else:
            print('The game is tied. Try again.')
            winner = 'tied'

    if computer_choice == 3:
        if player_choice == 1:
            print('Rock smashes scissors. You win!')
            winner = 'player'

        elif player_choice == 2:
            print('Scissors cut paper. The computer wins!')
            winner = 'computer'

        else:
            print('The game is tied. Try again.')
            winner = 'tied'

    return winner

main()

---

您不再分配给

计算机选项

或

玩家选项

，而是使用它的值

while play_again == 'y' or play_again == 'Y':

    process_computer_choice()

    process_player_choice()

应该是

while play_again == 'y' or play_again == 'Y':

    computer_choice = process_computer_choice()

    player_choice = process_player_choice()

至于戒烟，就打断你的选择吧。你必须从过程中提前回来，也要在主要方面做些事情

因此，在选择过程中：

if player_choice == 4:
    print('Exiting program....')
    return

总的来说： 玩家选择=过程玩家选择（）

---

对于问题1，这是因为您在循环之前设置了计算机和播放器选项，并且从不更新它们。将循环的开头更改为：

while play_again == 'y' or play_again == 'Y':
    computer_choice = process_computer_choice()
    player_choice = process_player_choice()

您还可以删除循环前检查输入和赢家的代码行，因为在第一轮中这在技术上是多余的

对于问题2，只需在选择4后添加结果，如下所示：

if player_choice == 4:
      print('Exiting program....')  
      print('there was', tied_games, 'tied games.')
      print('the player won', player_games, 'games.')
      print('The computer won', computer_games,'games.')
      sys.exit() # be sure you add 'import sys' to the beginning of your file

---

此外，主循环

determine\u winner（player\u choice，computer\u choice）

中的行缩进，因此只有当计算机选择剪刀时才会调用它，因此您应该取消提示：）

只需使用return而不是sys.exit检查main调用的函数中player choice是否为4，所以这不需要退出吗？显然，最好的方法是检入main（），但对于他的结构，这不是正确的吗？这正是我所需要的。谢谢<代码>如果player_choice==4:不在循环中，因此不能使用break，则可以使用return@PadraicCunningham，`while play_reach=='y'或play_reach=='y'：`不是循环吗？我的解决方案是，在第一轮退出不会起任何作用，但之后会正常工作。它可能不是理想的。if语句在OP代码的while循环之外，将返回work@PadraicCunningham，您的第一个选择是正确的，return将起作用，但对于循环中的选择，break是正确的，因为它将在之后打印结果，然后退出。我还错过了添加输入函数的返回。

if player_choice == 4:
      print('Exiting program....')  
      print('there was', tied_games, 'tied games.')
      print('the player won', player_games, 'games.')
      print('The computer won', computer_games,'games.')
      sys.exit() # be sure you add 'import sys' to the beginning of your file