Python 如何使用计数器汇总defaultdict中列表中的元组值？_Python_Python 3.x

Python 如何使用计数器汇总defaultdict中列表中的元组值？

python python-3.x

Python 如何使用计数器汇总defaultdict中列表中的元组值？,python,python-3.x,Python,Python 3.x,我有一个defaultdict，它将值分组为元组列表。我想使用计数器添加每个键的值因此，问题是如何转换： dict\u项目([ ("第一",("一","七","一","二","一","十二",，（'Key_Two'，[（'1'，13），（'1'，9），（'1'，7），（'1'，12），（'1'，2），（'1'，10）]） ]) 为此： [ 'Key_One'：计数器（{'1'：23，'5'：1}） 'Key_Two'：计数器（{'1'：53}） ] 使用collections.defaul

我有一个

defaultdict

，它将值分组为元组列表。我想使用

计数器添加每个键的值
因此，问题是如何转换：
dict\u项目([
("第一",("一","七","一","二","一","十二",，
（'Key_Two'，[（'1'，13），（'1'，9），（'1'，7），（'1'，12），（'1'，2），（'1'，10）]）
])

为此：
[
'Key_One'：计数器（{'1'：23，'5'：1}）
'Key_Two'：计数器（{'1'：53}）
]
使用collections.defaultdict
和一个简单的迭代
Ex:
from collections import defaultdict

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = defaultdict(int)
    for m, n in v:
        temp[m] += n
    result[k] = temp
print(result)

{'Key_One': defaultdict(<class 'int'>, {'1': 23, '5': 1}), 'Key_Two': defaultdict(<class 'int'>, {'1': 53})}

from collections import Counter

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = Counter()
    for m, n in v:
        temp.update(Counter({m:n}))
    result[k] = temp
print(result)

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

输出：
from collections import defaultdict

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = defaultdict(int)
    for m, n in v:
        temp[m] += n
    result[k] = temp
print(result)

{'Key_One': defaultdict(<class 'int'>, {'1': 23, '5': 1}), 'Key_Two': defaultdict(<class 'int'>, {'1': 53})}

from collections import Counter

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = Counter()
    for m, n in v:
        temp.update(Counter({m:n}))
    result[k] = temp
print(result)

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

输出：
from collections import defaultdict

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = defaultdict(int)
    for m, n in v:
        temp[m] += n
    result[k] = temp
print(result)

{'Key_One': defaultdict(<class 'int'>, {'1': 23, '5': 1}), 'Key_Two': defaultdict(<class 'int'>, {'1': 53})}

from collections import Counter

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = Counter()
    for m, n in v:
        temp.update(Counter({m:n}))
    result[k] = temp
print(result)

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

使用collections.defaultdict
和一个简单的迭代
Ex:
from collections import defaultdict

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = defaultdict(int)
    for m, n in v:
        temp[m] += n
    result[k] = temp
print(result)

{'Key_One': defaultdict(<class 'int'>, {'1': 23, '5': 1}), 'Key_Two': defaultdict(<class 'int'>, {'1': 53})}

from collections import Counter

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = Counter()
    for m, n in v:
        temp.update(Counter({m:n}))
    result[k] = temp
print(result)

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

输出：
from collections import defaultdict

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = defaultdict(int)
    for m, n in v:
        temp[m] += n
    result[k] = temp
print(result)

{'Key_One': defaultdict(<class 'int'>, {'1': 23, '5': 1}), 'Key_Two': defaultdict(<class 'int'>, {'1': 53})}

from collections import Counter

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = Counter()
    for m, n in v:
        temp.update(Counter({m:n}))
    result[k] = temp
print(result)

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

输出：
from collections import defaultdict

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = defaultdict(int)
    for m, n in v:
        temp[m] += n
    result[k] = temp
print(result)

{'Key_One': defaultdict(<class 'int'>, {'1': 23, '5': 1}), 'Key_Two': defaultdict(<class 'int'>, {'1': 53})}

from collections import Counter

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = Counter()
    for m, n in v:
        temp.update(Counter({m:n}))
    result[k] = temp
print(result)

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

使用计数器和defaultdict。Python 3.6.7
from collections import Counter
from collections import defaultdict

a = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
          ])

l = {}
for i in a:
    output = defaultdict(int)
    for k, v in a[i]:
        output[k] += v
    l.update({i: Counter(dict(output.items()))})

print(l)

输出：
from collections import defaultdict

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = defaultdict(int)
    for m, n in v:
        temp[m] += n
    result[k] = temp
print(result)

{'Key_One': defaultdict(<class 'int'>, {'1': 23, '5': 1}), 'Key_Two': defaultdict(<class 'int'>, {'1': 53})}

from collections import Counter

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = Counter()
    for m, n in v:
        temp.update(Counter({m:n}))
    result[k] = temp
print(result)

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

使用计数器和defaultdict。Python 3.6.7
from collections import Counter
from collections import defaultdict

a = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
          ])

l = {}
for i in a:
    output = defaultdict(int)
    for k, v in a[i]:
        output[k] += v
    l.update({i: Counter(dict(output.items()))})

print(l)

输出：
from collections import defaultdict

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = defaultdict(int)
    for m, n in v:
        temp[m] += n
    result[k] = temp
print(result)

{'Key_One': defaultdict(<class 'int'>, {'1': 23, '5': 1}), 'Key_Two': defaultdict(<class 'int'>, {'1': 53})}

from collections import Counter

d = dict([
    ('Key_One', [('1', 7), ('1', 2), ('1', 2), ('1', 12), ('5', 1)]),
    ('Key_Two', [('1', 13), ('1', 9), ('1', 7), ('1', 12), ('1', 2), ('1', 10)])
])

result = {}
for k, v in d.items():
    temp = Counter()
    for m, n in v:
        temp.update(Counter({m:n}))
    result[k] = temp
print(result)

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}

{'Key_One': Counter({'1': 23, '5': 1}), 'Key_Two': Counter({'1': 53})}