Python 比较列表并获取每个元素的匹配百分比

我有两个python列表

A= ['today is sunday', 'today is wednesday']
B= ['today is sunday', 'today is 
     Monday'....'today is Saturday']

 For elm in A:
     If elm in B:
        print ("not ok")
      else:
        print ("ok")

我想计算两个python列表中元素的匹配百分比

A= ['today is sunday', 'today is wednesday']
B= ['today is sunday', 'today is 
     Monday'....'today is Saturday']

 For elm in A:
     If elm in B:
        print ("not ok")
      else:
        print ("ok")

所需的匹配百分比计算如图所示：

它可以是：

A= ['today is sunday', 'today is wednesday']
B= ['today is sunday', 'today is monday', 'today is Saturday']
match_percent = (len(set(B).intersection(set(A))))/len(B)*100
print(match_percent)

---

我不确定您要计算的匹配百分比，所以我冒昧地计算为match\u count/maxlist\u a\u size，list\u b\u size

输出：

0.3333333333333333