Python 打印另一个文件的内容，并在输入错误时循环原始输入

我正在做一个应用程序，必须为它做一个简短的屏幕手册。为了不让脚本中再出现100行“打印这个，打印那个”，我把它写在了一个单独的文件中。但是，我不知道如何打印另一个文件的内容

我还遇到了此循环的问题：

if option == 'help':
    print "content of the help file"
elif option == 'start':
    run(host='localhost', port=8080)
else:
    print "not a valid option, try again"

在循环结束时，如果用户输入了一个无效选项，我如何使其可以重试而不必再次执行该文件

如需打印文件，请阅读

使用while循环

---

假设您的帮助内容位于名为

help.txt的文件中：

validInputs = set(["help", "start"])
userInput = raw_input("What would you like to do? ").strip()
while userInput not in validInputs:
    print "That was an incorrect input. Try again"
    userInput = raw_input("What would you like to do? ").strip()
if userInput == 'help':  # print contents of help file
    with open('help.txt') as infile:
        for line in infile:
            print line.rstrip()
elif userInput == 'start':
    run(host='localhost', port=8080)

在您的while条件下，
或
应该是
和
；即使
选项
是
'start'
，条件也会传递给
选项！='“帮助”
，while将重新执行@inspectorG4dget谢谢！我犯了一个愚蠢的错误。
validInputs = set(["help", "start"])
userInput = raw_input("What would you like to do? ").strip()
while userInput not in validInputs:
    print "That was an incorrect input. Try again"
    userInput = raw_input("What would you like to do? ").strip()
if userInput == 'help':  # print contents of help file
    with open('help.txt') as infile:
        for line in infile:
            print line.rstrip()
elif userInput == 'start':
    run(host='localhost', port=8080)