Python 使用pandas时发生sqlite3.0错误,无任何解释

Python 使用pandas时发生sqlite3.0错误,无任何解释,python,pandas,sqlite,Python,Pandas,Sqlite,我正在尝试运行以下代码以从sqlite获取CSV: import sqlite3 import pandas as pd con = sqlite3.connect("Cerner.db") with open('query.sql', 'r') as file: query = file.read() df = pd.read_sql_query(query, con) df.to_pickle('raw_data.df') df.to_csv('raw

我正在尝试运行以下代码以从sqlite获取CSV:

import sqlite3
import pandas as pd

con = sqlite3.connect("Cerner.db")
with open('query.sql', 'r') as file:
    query = file.read()
df = pd.read_sql_query(query, con)
    
df.to_pickle('raw_data.df')
df.to_csv('raw_data.csv', index = False
查询如下:

WITH diagnoses AS 
(
    SELECT
        F.ENCOUNTER_ID,
        D.DIAGNOSIS_TYPE,
        D.DIAGNOSIS_CODE
    FROM
        HF_F_DIAGNOSIS AS F
    LEFT JOIN 
        HF_D_DIAGNOSIS AS D ON F.DIAGNOSIS_ID = D.DIAGNOSIS_ID
)
SELECT
    enc.ENCOUNTER_ID,
    enc.PATIENT_ID,
    enc.AGE_IN_YEARS,
    pat.RACE,
    pat.GENDER,
    p_type.PATIENT_TYPE_DESC,
    enc.ADMITTED_DT_TM,
    diagnoses.DIAGNOSIS_TYPE,
    diagnoses.DIAGNOSIS_CODE
FROM
    HF_F_ENCOUNTER AS enc
LEFT JOIN 
    HF_D_PATIENT_TYPE AS p_type ON enc.PATIENT_TYPE_ID = p_type.PATIENT_TYPE_ID
LEFT JOIN 
    diagnoses ON enc.ENCOUNTER_ID = diagnoses.ENCOUNTER_ID
LEFT JOIN 
    HF_D_PATIENT AS pat on  enc.PATIENT_ID = pat.PATIENT_ID
WHERE 
    enc.ENCOUNTER_ID = diagnoses.ENCOUNTER_ID;
运行
cur.fetchall()
时,如果没有详细信息,则会引发
sqlite3.OperationalError

如果我仅像这样限制查询,它就可以正常工作:

WITH diagnoses AS 
(
    SELECT
        ...
    FROM
        ...
    LIMIT 1000
)
SELECT
    ...
FROM
    ...
LIMIT 1000;
有人能帮我弄明白怎么修吗

谢谢大家!