&引用;TypeError:列表索引必须是整数或切片,而不是非类型";在Tictaoe游戏中(Python 3)

&引用;TypeError:列表索引必须是整数或切片,而不是非类型";在Tictaoe游戏中(Python 3),python,typeerror,slice,indices,Python,Typeerror,Slice,Indices,我一直在用Python3开发一个基本的Tictatcoe游戏,玩家与AI竞争以赢得比赛。在第一个回合中,代码成功执行,没有错误,但之后我得到了前面描述的错误 我曾尝试将“board[move]=computer”改为“move=computer”,但这只是跳过了计算机的轮换,因为没有填写任何内容 我期望Tictatcoe板的输出带有一个新的填充有“O”的方块。但我得到的错误是“板[移动]=计算机” TypeError:列表索引必须是整数或切片,而不是非类型“ 代码如下: X = "X" O =

我一直在用Python3开发一个基本的Tictatcoe游戏,玩家与AI竞争以赢得比赛。在第一个回合中,代码成功执行,没有错误,但之后我得到了前面描述的错误

我曾尝试将“board[move]=computer”改为“move=computer”,但这只是跳过了计算机的轮换,因为没有填写任何内容

我期望Tictatcoe板的输出带有一个新的填充有“O”的方块。但我得到的错误是“板[移动]=计算机” TypeError:列表索引必须是整数或切片,而不是非类型“

代码如下:

X = "X"
O = "O"
EMPTY = " "
TIE = "TIE"
NUM_SQUARES = 9

def pieces():
    go_first = ask_yes_no("Do you require the first move? (y/n): ")
    if go_first == "y":
        print("\nThen take the first move. You will need it.")
        human = X
        computer = O
    else:
        print("\nYour bravery will be your undoing... I'll go first")
        computer = X
        human = O
    return computer, human

def new_board():
    board = []
    for square in range(NUM_SQUARES):
        board.append(EMPTY)
    return board

def legal_moves(board):
    moves = []
    for square in range(NUM_SQUARES):
        if board[square] == EMPTY:
            moves.append(square)
        return moves

def winner(board):
    WAYS_TO_WIN = ((0, 1, 2),
                  (3, 4, 5),
                  (6, 7, 8),
                  (0, 3, 6),
                  (1, 4, 7),
                  (2, 5, 8),
                  (0, 4, 8),
                  (2, 4, 6))

    for row in WAYS_TO_WIN:
        if board[row[0]] == board[row[1]] == board[row[2]] != EMPTY:
            winner = board[row[0]]
            return winner

    if EMPTY not in board:
        return TIE

    return None


def human_move(board, human):
    legal = legal_moves(board)
    move = None
    while move not in legal:
        move = ask_number("Where will you move? (0 - 8):", 0, 
                           NUM_SQUARES)
        if move not in legal:
            print("\nThat square is already occupied. Choose another.\n")
        print("Fine...")
        return move


def computer_move(board, computer, human):
    board = board[:]

    BEST_MOVES = (4, 0, 2, 6, 8, 1, 3, 5, 7)

    print("I shall take square number", end=" ")

    for move in legal_moves(board):
        board[move] = computer
        if winner(board) == computer:
            print(move)
            return move
        board[move] = EMPTY

    for move in legal_moves(board):
        board[move] = human
        if winner(board) == human:
            print(move)
            return move
        board[move] = EMPTY

    for move in BEST_MOVES:
        if move in legal_moves(board):
            print(move)
            return move

def next_turn(turn):
    if turn == X:
        return O
    else:
        return X


def main():
    computer, human = pieces()
    turn = X
    board = new_board()
    display_board(board)

    while not winner(board):
        if turn == human:
            move = human_move(board, human)
            board[move] = human
        else:
            move = computer_move(board, computer, human)
            board[move] = computer

        display_board(board)
        turn = next_turn(turn)

    the_winner = winner(board)

main()

您的legal_moves函数被破坏,因为无论发生什么情况,它都会在第一个'sqare'之后返回。如果它已被删除,它将返回一个空列表

只需向下移动
返回
指令:

def legal_moves(board):
    moves = []
    for square in range(NUM_SQUARES):
        if board[square] == EMPTY:
            moves.append(square)
    return moves