使用python中另一个列表的索引打印列表的元素

我有以下带有赋值的变量

data_row=["Summary","Description","Date","comment","comment","comment"]
summary_column=0
comment_colomn=[3,4,5]

我只需要打印摘要和评论字段，如下所示

Summery comment comment comment

我用下面的代码尝试了这一点，但它没有正确地给出输出

print(data_row[summary_column]+" ".join([data_row(clmn) for clmn in comment_column]))

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您可以使用以下列表获取注释列的列表：

[data_row[i] for i in comment_colomn]

然后将其添加到摘要列表中

data_row=["Summary","Description","Date","comment","comment","comment"]
summary_column=0
comment_colomn=[3,4,5]

print([data_row[summary_column]] + [data_row[i] for i in comment_colomn])

您还可以修改此选项，以使用join

print(" ".join([data_row[summary_column]] + [data_row[i] for i in comment_colomn]))

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您可以尝试以下代码段：

data_row=["Summary","Description","Date","comment","comment","comment"]
summary_column = 0
comment_column = [3,4,5]

print([data_row[summary_column]] + [data_row[i] for i in comment_column])

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您好，您可以将其用于数据行[摘要列]部分 1>

2> printdata_行[摘要_列]+。将[data_行[clmn]加入注释_列中的clmn]

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您在过去的代码中出现了一些语法错误，这就是它不起作用的原因。列表索引不能用这些来调用，但这些[]

您在代码注释栏的最后一个列表中有一个拼写错误，在您的打印中您有。。。评论栏

Summary comment comment comment

data_row=["Summary","Description","Date","comment","comment","comment"]
summary_column = 0
comment_column = [3,4,5]

print([data_row[summary_column]] + [data_row[i] for i in comment_column])

for i in comment_colomn:
    print(data_row[i])