Python 不创建它应该创建的csv文件

我希望获得类似以下内容的csv文件：

index,Basic Mechanics,Basic Thermodynamics,Calculus I,Calculus II,Chemistry I,Chemistry II,Engineering Drawing,Fundamentals of Informatics,Geometry,Linear Algebra
ATTEMPTS,1.416,1.404,1.421,1.347,1.305,1.246,1.261,1.456,1.325,1.385

我有以下代码：

attempts=pd.read_csv("attempts.csv",sep=',', delimiter=None, header='infer')
a2=attempts[(attempts["HSCHOOL"]=="hs1")]
df=a2[["Subject","ATTEMPTS"]]
def subjects_hs(df):
    df=df.pivot_table(columns="Subject",values="ATTEMPTS")
    df=df.reset_index()
    df=df.round(decimals=3)
    df.to_csv("attempts_hs.csv",index=False)

其中，truments.csv如下所示：

AC_YEAR,HSCHOOL,Subject,ATTEMPTS
2010,hs1,Linear Algebra,2
2010,hs1,Calculus I,1
2010,hs1,Basic Mechanics,2
2010,hs1,Chemistry I,2
2010,hs3,Fundamentals of Informatics,2
2010,hs2,Calculus II,1
2010,hs1,Basic Thermodynamics,1
2010,hs3,Linear Algebra,1
2010,hs3,Calculus I,1
2010,hs2,Basic Mechanics,1
2010,hs2,Chemistry I,1
2010,hs2,Fundamentals of Informatics,1

相反，我得到了以下文件：

Subject,ATTEMPTS
Basic Mechanics,1.545
Basic Thermodynamics,1.667
Calculus I,1.545
Calculus II,1.545
Chemistry I,1.667
Chemistry II,1.4
Engineering Drawing,1.692
Fundamentals of Informatics,2.0
Geometry,1.583
Linear Algebra,1.5

---

这不是我想要的格式（我希望所有内容都在一行中！）。当我在python中尝试它时，它正常工作，但在pythonywhere中不工作。。。有什么想法吗？谢谢

下面的代码似乎对我有用

attempts=pd.read_csv("attempts.csv",sep=',', delimiter=None, header='infer')
a2=attempts[(attempts["HSCHOOL"]=="hs1")]
df=a2[["Subject","ATTEMPTS"]]
def subjects_hs(df):
    df=df.pivot_table(columns="Subject",values=["ATTEMPTS"])
    df=df.reset_index()
    df=df.round(decimals=3)
    df.to_csv("attempts_hs.csv",index=False)

pivot_表的“values”参数为列表时提供了预期的行为

第5行：将

values=“ATTEMPTS”

更改为

values=[“ATTEMPTS”]