如何在Python中打印另一个字典中的键和深层嵌套dict中的值

下面是我的字典。如何在Python中打印另一个字典中的键和深层嵌套dict中的值

my_nested_dict = {"global": {"peers": {"15.1.1.1": {"remote_id": "15.1.1.1", "address_family": {"ipv4": {"sent_prefixes": 1, "received_prefixes": 4, "accepted_prefixes": 4}}, "remote_as": 65002, "uptime": 13002, "is_enabled": True, "is_up": True, "description": "== R3 BGP Neighbor ==", "local_as": 65002}}, "router_id": "15.1.1.2"}}
filtered_list = ['peers', 'remote_id', 'remote_as', 'uptime']
filtered_map_dict = {'peers':'pe', 'remote_id':'id', 'remote_as':'as', 'uptime':'up'}
def seek_keys(d, key_list):
     for k, v in d.items():
            if k in key_list:
                if isinstance(v, dict):
                    print(k + ": " + list(v.keys())[0])
                else:
                    print(k + ": " + str(v))
            if isinstance(v, dict):
                seek_keys(v, key_list)

seek_keys(my_nested_dict, filtered_list)

我的输出：

peers: 15.1.1.1
remote_id: 15.1.1.1
remote_as: 65002
uptime: 13002

pe: 15.1.1.1
id: 15.1.1.1
as: 65002
up: 13002

def seek_keys(d, key_list, filter_list):
    for k, v in d.items():
        if k in key_list:
            if isinstance(v, dict):
                print(filter_list[k] + ": " + list(v.keys())[0])
            else:
                print(filter_list[k] + ": " + str(v))
        if isinstance(v, dict):
            seek_keys(v, key_list, filter_list)


seek_keys(my_nested_dict, filtered_list, filtered_map_dict)

>>> python3 test.py 
pe: 15.1.1.1
id: 15.1.1.1
as: 65002
as: 13002  # It should be "as" based on your filtered_map_dict. (Not "up" as you have written in your question.)

预期输出：

peers: 15.1.1.1
remote_id: 15.1.1.1
remote_as: 65002
uptime: 13002

pe: 15.1.1.1
id: 15.1.1.1
as: 65002
up: 13002

def seek_keys(d, key_list, filter_list):
    for k, v in d.items():
        if k in key_list:
            if isinstance(v, dict):
                print(filter_list[k] + ": " + list(v.keys())[0])
            else:
                print(filter_list[k] + ": " + str(v))
        if isinstance(v, dict):
            seek_keys(v, key_list, filter_list)


seek_keys(my_nested_dict, filtered_list, filtered_map_dict)

>>> python3 test.py 
pe: 15.1.1.1
id: 15.1.1.1
as: 65002
as: 13002  # It should be "as" based on your filtered_map_dict. (Not "up" as you have written in your question.)

---

您需要打印

filter\u list[k]

而不是简单的

k

。我已经编写了一个示例代码，它提供了预期的输出

代码：

peers: 15.1.1.1
remote_id: 15.1.1.1
remote_as: 65002
uptime: 13002

pe: 15.1.1.1
id: 15.1.1.1
as: 65002
up: 13002

def seek_keys(d, key_list, filter_list):
    for k, v in d.items():
        if k in key_list:
            if isinstance(v, dict):
                print(filter_list[k] + ": " + list(v.keys())[0])
            else:
                print(filter_list[k] + ": " + str(v))
        if isinstance(v, dict):
            seek_keys(v, key_list, filter_list)


seek_keys(my_nested_dict, filtered_list, filtered_map_dict)

>>> python3 test.py 
pe: 15.1.1.1
id: 15.1.1.1
as: 65002
as: 13002  # It should be "as" based on your filtered_map_dict. (Not "up" as you have written in your question.)

输出：

peers: 15.1.1.1
remote_id: 15.1.1.1
remote_as: 65002
uptime: 13002

pe: 15.1.1.1
id: 15.1.1.1
as: 65002
up: 13002

def seek_keys(d, key_list, filter_list):
    for k, v in d.items():
        if k in key_list:
            if isinstance(v, dict):
                print(filter_list[k] + ": " + list(v.keys())[0])
            else:
                print(filter_list[k] + ": " + str(v))
        if isinstance(v, dict):
            seek_keys(v, key_list, filter_list)


seek_keys(my_nested_dict, filtered_list, filtered_map_dict)

>>> python3 test.py 
pe: 15.1.1.1
id: 15.1.1.1
as: 65002
as: 13002  # It should be "as" based on your filtered_map_dict. (Not "up" as you have written in your question.)

如果您将您的

过滤地图\u dict

更改为：

filtered_map_dict = {"peers": "pe", "remote_id": "id", "remote_as": "as", "uptime": "up"}

正如您在下面看到的，输出将完全符合您的要求

>>> python3 test.py 
pe: 15.1.1.1
id: 15.1.1.1
as: 65002
up: 13002

---

只需打印

filtered\u map\u dict[k]

而不是

k

。