如何使用python和ruamel更新此yaml文件?
我有一个test.yaml文件,其中包含以下内容:如何使用python和ruamel更新此yaml文件?,python,file,yaml,pyyaml,ruamel.yaml,Python,File,Yaml,Pyyaml,Ruamel.yaml,我有一个test.yaml文件,其中包含以下内容: school_ids: school1: "001" #important school2 school2: "002" targets: neighborhood1: schools: - school1-paloalto teachers: - 33 neighborhood2: schools: - school2
school_ids:
school1: "001"
#important school2
school2: "002"
targets:
neighborhood1:
schools:
- school1-paloalto
teachers:
- 33
neighborhood2:
schools:
- school2-paloalto
teachers:
- 35
我想使用ruamel将文件更新为如下所示:
school_ids:
school1: "001"
#important school2
school2: "002"
school3: "003"
targets:
neighborhood1:
schools:
- school1-paloalto
teachers:
- 33
neighborhood2:
schools:
- school2-paloalto
teachers:
- 35
neighborhood3:
schools:
- school3-paloalto
teachers:
- 31
如何使用ruamel通过保留注释来更新文件以获得所需的输出
以下是我目前掌握的情况:
import sys
from ruamel.yaml import YAML
inp = open('/targets.yaml', 'r').read()
yaml = YAML()
code = yaml.load(inp)
account_ids = code['school_ids']
account_ids['new_school'] = "003"
#yaml.dump(account_ids, sys.stdout)
targets = code['targets']
new_target = dict(neighborhood3=dict(schools=["school3-paloalto"], teachers=["31"]))
yaml = YAML()
yaml.indent(mapping=2, sequence=3, offset=2)
yaml.dump(new_target, sys.stdout)
您只是在转储从头创建的
新目标
,而不是使用代码
甚至目标
。
相反,您应该使用该code
that
加载并扩展与其根级别键关联的值,然后转储code
:
import sys
from pathlib import Path
from ruamel.yaml import YAML
inp = Path('test.yaml')
yaml = YAML()
code = yaml.load(inp)
school_ids = code['school_ids']
school_ids['school3'] = "003"
targets = code['targets']
targets['neighborhood3'] = dict(schools=["school3-paloalto"], teachers=["31"])
yaml = YAML()
yaml.indent(mapping=2, sequence=4, offset=2)
yaml.dump(code, sys.stdout)
其中:
school_ids:
school1: '001'
#important school2
school2: '002'
school3: '003'
targets:
neighborhood1:
schools:
- school1-paloalto
teachers:
- 33
neighborhood2:
schools:
- school2-paloalto
teachers:
- 35
neighborhood3:
schools:
- school3-paloalto
teachers:
- '31'
请注意,您的序列缩进需要至少比您的序列缩进大2
偏移(2个位置有空间容纳-
+空间)
输出在键school2
之后有emtpy行,这就是
在解析过程中,这些与关联。可以将其移动到新关键点,但
这不是小事。如果您需要这样做(这对于语义来说并不重要)
然后看看我的答案
感谢您的友好和及时回复@Anthon。我注意到,在我下面的示例中,您的回答中也提到了,我们正在sys.stdout中打印。是否有方法更新同一文件并将更新的字段和值写入其中?使用相同的ruamel模块。正在更新文件。。。提前谢谢你@贝克:如果您使用的是
pathlib.Path
实例(和我一样),那么写回文件就像执行yaml.dump(code,inp)
一样简单。适当的操作将为您打开和关闭文件。如果输出应该转到不同的文件(或者如果需要保存旧的文件内容,请考虑重命名<代码> Inp< /Cord>),请新建一个<代码>路径>代码>