Python 我得到TypeError:can'；t将序列乘以类型为'的非整数；浮动'；

我收到了TypeError：在运行代码时，无法将序列与“float”类型的非int相乘。有人能给我解释一下问题是什么吗？基本上，我正在做一个用于家庭作业的孔径计算器

import time as t #imports time so the code will look much better.
import random #imports random
import math #imports math

pih = ()
inputs = [] #Brackets to make it a list

#All the functions
def x_round(x): #A function that rounds the thing inside the bracket the next 0.25w
  return math.ceil(x*4)/4 #whenever x_round something, goes to nearest 0.25

def isFloat(x):
  try:
    float(x)
    inputs.append("float")
    float(x)
  except ValueError:
    inputs.append("why")


print("Bore Size Caculator")
print("========================")

while 1 == 1:
  choice = input("Would you like to determine the bore-size (B) or the volume (V) of the tunnel? ")

  pi = 3.14159265358979 #Gets variable pi as the number pi
  choice=choice.lower()

  if choice == "b":
    volume=input("What is the minimum volume that is required? (cubic metres): ")
    height=input("How long do you need the tunnel to be? (metres): ")
    isFloat(volume)
    isFloat(height)
    isfloat=inputs[-1]
    if isfloat == "float":
      float(height)
      float(volume)
      print(pi)
      print(height)
      pih = pi * height
      vpih = volume / pih
      radius = math.sqrt(vpih)
      roundedradius = x_round(radius)
      if roundedradius > 8:  
        increased=volume/(pi*(64))
        increased=round(increased , 2)
        print("There is no bore size big enough, increase the legnth to",increased)
      elif roundedradius <= 8:
        print("Bore radius size required:",roundedradius)
        exactvolume = round(pih *( roundedradius * roundedradius ), 2)
        print("Exact volume produced (with bore-size above and the tunnel legnth specified)",exactvolume)
    else:
      print("Please input a valid number")

  print("========================")

导入时间，因为t#导入时间，所以代码看起来会更好。
导入随机#导入随机
导入数学#导入数学
pih=（）
inputs=[]#括号将其列为一个列表
#所有功能
def x#u round（x）：#一个函数，它将括号内的对象旋转0.25w
返回math.ceil（x*4）/4#每当x#u取整某物时，都精确到0.25
def isFloat（x）：
尝试：
浮动（x）
输入。追加（“浮动”）
浮动（x）
除值错误外：
inputs.append（“为什么”）
打印（“孔径计算器”）
打印（“=====================================”）
而1==1：
选择=输入（“您想确定隧道的钻孔尺寸（B）还是体积（V？”）
pi=3.14159265358979#获取变量pi作为数字pi
choice=choice.lower（）
如果选项==“b”：
体积=输入（“所需的最小体积是多少？（立方米）：”）
高度=输入（“隧道需要多长？（米）：”）
isFloat（体积）
isFloat（高度）
isfloat=输入[-1]
如果isfloat==“float”：
浮子（高度）
浮动（体积）
打印（pi）
打印（高度）
pih=pi*高度
vpih=体积/pih
半径=数学sqrt（vpih）
圆形半径=x_圆形（半径）
如果圆形半径>8：
增加=体积/（pi*（64））
增加=轮数（增加，2）
打印（“没有足够大的孔尺寸，将长度增加到”，增加）
elif roundedradius要更改类型的变量，例如
a
，仅执行
float（a）
，是不够的，因为您必须指定此
a=float（a）
，因为您使用
高度
和
体积
时，我多次将其转换为float，如下所示：

   volume=float(input("What is the minimum volume that is required? (cubic metres): "))
        height=float(input("How long do you need the tunnel to be? (metres): "))

避免以下行中的所有错误

import time as t #imports time so the code will look much better.
import random #imports random
import math #imports math

pih = ()
inputs = [] #Brackets to make it a list

#All the functions
def x_round(x): #A function that rounds the thing inside the bracket the next 0.25w
  return math.ceil(x*4)/4 #whenever x_round something, goes to nearest 0.25

def isFloat(x):
  try:
    float(x)
    inputs.append("float")
    float(x)
  except ValueError:
    inputs.append("why")


print("Bore Size Caculator")
print("========================")

while 1 == 1:
  choice = input("Would you like to determine the bore-size (B) or the volume (V) of the tunnel? ")

  pi = 3.14159265358979 #Gets variable pi as the number pi
  choice=choice.lower()

  if choice == "b":
    volume=float(input("What is the minimum volume that is required? (cubic metres): "))
    height=float(input("How long do you need the tunnel to be? (metres): "))
    isFloat(volume)
    isFloat(height)
    isfloat=inputs[-1]
    if isfloat == "float":
      print(pi)
      print(height)
      pih = pi * height
      vpih = volume / pih
      radius = math.sqrt(vpih)
      roundedradius = x_round(radius)
      if roundedradius > 8:  
        increased=volume/(pi*(64))
        increased=round(increased , 2)
        print("There is no bore size big enough, increase the legnth to",increased)
      elif roundedradius <= 8:
        print("Bore radius size required:",roundedradius)
        exactvolume = round(pih *( roundedradius * roundedradius ), 2)
        print("Exact volume produced (with bore-size above and the tunnel legnth specified)",exactvolume)
    else:
      print("Please input a valid number")

  print("========================")

是否有办法防止回溯（最近一次调用最后一次）：“File”program.py，第31行，volume=float（输入（“所需的最小体积是多少？（立方米）：”）ValueError:如果用户输入的内容不是数字，则无法将字符串转换为浮点：“agsfjhgasf”？我已使用此改进更新了代码。看看代码。嗨，欢迎来到堆栈溢出。虽然您已经收到了一个答案，希望是一个有帮助的答案，但请注意（对于将来的问题），准确地说出错误的来源（它在回溯中显示），以及如何提供一个仍然再现错误的最小示例（作为旁注，这也是调试过程中有用的一部分）是很重要的。要了解更多信息，请访问：。祝你好运和快乐！
import time as t #imports time so the code will look much better.
import random #imports random
import math #imports math

pih = ()
inputs = [] #Brackets to make it a list

#All the functions
def x_round(x): #A function that rounds the thing inside the bracket the next 0.25w
    return math.ceil(x*4)/4 #whenever x_round something, goes to nearest 0.25

def isFloat(x):
    try:
        float(x)
        inputs.append("float")
        float(x)
    except ValueError:
        inputs.append("why")


print("Bore Size Caculator")
print("========================")
choice=0
while choice !='q':
    choice = input("Would you like to determine the bore-size (B) or the volume (V) of the tunnel or exit (Q)? ")

    pi = 3.14159265358979 #Gets variable pi as the number pi
    choice=choice.lower()

    if choice == "b":
        enter=False
        while enter==False:
            try:
                volume=float(input("What is the minimum volume that is required? (cubic metres): "))
                height=float(input("How long do you need the tunnel to be? (metres): "))
                enter=True
                print(pi)
                print(height)
                pih = pi * height
                vpih = volume / pih
                radius = math.sqrt(vpih)
                roundedradius = x_round(radius)
                if roundedradius > 8:  
                    increased=volume/(pi*(64))
                    increased=round(increased , 2)
                    print("There is no bore size big enough, increase the legnth to",increased)
                elif roundedradius <= 8:
                    print("Bore radius size required:",roundedradius)
                    exactvolume = round(pih *( roundedradius * roundedradius ), 2)
                    print("Exact volume produced (with bore-size above and the tunnel legnth specified)",exactvolume)
            except:
                print("Please input a valid number")

    print("========================")

 Bore Size Caculator
========================
Would you like to determine the bore-size (B) or the volume (V) of the tunnel or exist (Q)? B
What is the minimum volume that is required? (cubic metres): 20
How long do you need the tunnel to be? (metres): 1000
3.14159265358979
1000.0
Bore radius size required: 0.25
Exact volume produced (with bore-size above and the tunnel legnth specified) 196.35
========================
Would you like to determine the bore-size (B) or the volume (V) of the tunnel or exist (Q)? B
What is the minimum volume that is required? (cubic metres): ABBDBDBBBF
Please input a valid number
What is the minimum volume that is required? (cubic metres): 12
How long do you need the tunnel to be? (metres): 200
3.14159265358979
200.0
Bore radius size required: 0.25
Exact volume produced (with bore-size above and the tunnel legnth specified) 39.27
========================
Would you like to determine the bore-size (B) or the volume (V) of the tunnel or exist (Q)? Q
========================