Python3.x代码的简短版本

Python3.x代码的简短版本,python,Python,有没有更简短的方法来检查字符串中的字符?谢谢:D check = input("Put in the letter: ") word = "word" if(check == word[0]): print(check) if(check == word[1]): print(check) if(check == word[2]): print(check) if(check == word[3]): print(check) 差不多 for l in wor

有没有更简短的方法来检查字符串中的字符?谢谢:D

check = input("Put in the letter: ")
word = "word"

if(check == word[0]):
    print(check)
if(check == word[1]):
    print(check)
if(check == word[2]):
    print(check)
if(check == word[3]):
    print(check)
差不多

for l in word:
      if l == check:
            print (check)
也许吧?

这个怎么样:

if check in word:
    print(check)

快速提示:@leistungsabfall的代码将打印字符一次,尽管它可能会出现多次,而我的代码与您的原始代码一样,如果字母在单词中出现多次,则会打印n次。这并不完全相同,例如,如果
word='HELLO'
check='L'