Python 另一个列表中列表中的项目

我有两份清单：

list1 = ['home', 'school', 'bus', football']
list2 = ['yesterday I went to home', 'I am busy', 385723, 'I feel like 
         playing football', I was tired last week', 'I go to school by 
         bus',' there is a bus stop near my home', 'I am hungry']

我想知道如何打印列表2中包含列表1中任何项目（至少1个）的任何项目？ 例如，在我们的示例中，应打印以下内容：

'yesterday I went to home','I feel like playing football', 'I go to school 
 by bus',' there is a bus stop near my home'

---

我写了一段代码，但我的应用程序在运行时中断：

    theList = []
    i = 0
    while i < len(list1):
        for element in list2:
            if (list1[i]) in element.lower():
                theList.append(element)
        i += 1
    print(errorList)

theList=[]
i=0
而我

试试这个！它来自内存，但应该可以工作：）

---

如果有错误，请告诉我，试试这个！它来自内存，但应该可以工作：）

如果出现错误，请告诉我，

尝试以下方法：

for string in list2:
    if(type(string)==str): #if the element in list2 is a string
        if(set(string.split()) & set(list1)): #split the string into words, and check if it has a set intersection with list1
            print(string)

输出：

yesterday I went to home
I feel like playing football
I go to school by bus
 there is a bus stop near my home

试试这个：

for string in list2:
    if(type(string)==str): #if the element in list2 is a string
        if(set(string.split()) & set(list1)): #split the string into words, and check if it has a set intersection with list1
            print(string)

输出：

yesterday I went to home
I feel like playing football
I go to school by bus
 there is a bus stop near my home

另一个解决方案：

print([el2 for el2 in list2 if any(el1 in str(el2).split() for el1 in list1)])

另一个解决方案：

print([el2 for el2 in list2 if any(el1 in str(el2).split() for el1 in list1)])

---

需要拆分成单词并匹配

list1 = ['home', 'school', 'bus', 'football']
list2 = ['yesterday I went to home', 'I am busy', 385723, 'I feel like playing football',
         'I was tired last week', 'I go to school by bus',' there is a bus stop near my home', 'I am hungry']

theList = []
for item2 in list2:
    for item1 in list1:
        bfound=False
        if type(item2) is  str:
            words = item2.lower().split()
            for word in words:
                if word==item1:
                    theList.append(item2)
                    bfound=True
                    break
            if bfound:
                break

print(theList)

输出

['yesterday I went to home', 'I feel like playing football', 'I go to school by bus', ' there is a bus stop near my home']

---

需要拆分成单词并匹配

list1 = ['home', 'school', 'bus', 'football']
list2 = ['yesterday I went to home', 'I am busy', 385723, 'I feel like playing football',
         'I was tired last week', 'I go to school by bus',' there is a bus stop near my home', 'I am hungry']

theList = []
for item2 in list2:
    for item1 in list1:
        bfound=False
        if type(item2) is  str:
            words = item2.lower().split()
            for word in words:
                if word==item1:
                    theList.append(item2)
                    bfound=True
                    break
            if bfound:
                break

print(theList)

输出

['yesterday I went to home', 'I feel like playing football', 'I go to school by bus', ' there is a bus stop near my home']

---

这是一个易于阅读的多行解决方案，它不考虑

list2

中不属于

string

类型的项：

result = []
for sentence in list2:
    if isinstance(sentence, str):
        for word in list1:
            if word in sentence.split():
                result.append(sentence)
                break
print(result)

这里还有一个单行样式的解决方案（我看到@grimek已经给出了它），它将

list2

中的任何项目转换为

string

类型：

result = [sentence for sentence in list2 if any(word in str(sentence).split() for word in list1)]
print(result)

---

这是一个易于阅读的多行解决方案，它不考虑

list2

中不属于

string

类型的项：

result = []
for sentence in list2:
    if isinstance(sentence, str):
        for word in list1:
            if word in sentence.split():
                result.append(sentence)
                break
print(result)

这里还有一个单行样式的解决方案（我看到@grimek已经给出了它），它将

list2

中的任何项目转换为

string

类型：

result = [sentence for sentence in list2 if any(word in str(sentence).split() for word in list1)]
print(result)

试试这个：-）

清单3的结果是

[“昨天我回家了”，“我想踢足球”，“我去上学了” “乘公共汽车上学”，“我家附近有一个公共汽车站”]

试试这个：-）

清单3的结果是

[“昨天我回家了”，“我想踢足球”，“我去上学了” “乘公共汽车上学”，“我家附近有一个公共汽车站”]

---

如果您直接检查字符串中的'bus'，可能会得到错误的结果，因为它会逐个检查sub_字符串，所以如果您在本例中执行此操作：

'bus' in 'I am busy' then it will return True :

因此，解决方案不是检查子字符串，而是逐字检查：

print([j for i in list1 for j in list2 if isinstance(j,str) if i in j.split()])

输出：

['yesterday I went to home', ' there is a bus stop near my home', 'I go to school by bus', 'I go to school by bus', ' there is a bus stop near my home', 'I feel like playing football']

---

如果您直接检查字符串中的'bus'，可能会得到错误的结果，因为它会逐个检查sub_字符串，所以如果您在本例中执行此操作：

'bus' in 'I am busy' then it will return True :

因此，解决方案不是检查子字符串，而是逐字检查：

print([j for i in list1 for j in list2 if isinstance(j,str) if i in j.split()])

输出：

['yesterday I went to home', ' there is a bus stop near my home', 'I go to school by bus', 'I go to school by bus', ' there is a bus stop near my home', 'I feel like playing football']

---

[a代表列表2中的a（如果有）（str中的s代表列表1中的s）]

“我的应用程序在运行时中断”需要更多详细信息<代码>[a代表列表2中的a（如果有）（str中的s代表列表1中的s）]“我的应用程序在运行时中断”需要更多详细信息。这会引发一个错误

TypeError:“int”对象不可编辑

原因是

列表中的元素
385723
，这会引发一个错误
TypeError:“int”对象不可编辑
原因是
列表中的元素
385723
you@VikasDamodar谢谢，和我的回答一样：）（和split对列表2中的数字
385723
不起作用）是的..类似，但只有一行..谢谢你的帮助..我完全忘记了：）我想那应该是“结果”而不是输出。和我的答案一样：）（和split对列表2中的数字
385723
不起作用）是的。。相似但只有一行。。谢谢你的帮助。。我完全忘记了：）我认为这应该是“结果”而不是输出。