Python 在字典内的列表上迭代

我是Python新手，我希望在字典中的列表中遍历字典，我知道

my_dict = {"John": [{"class": "math", "score": 100, "year": 2014}, {"class": "english", "score": 85, "year": 2015}], 
"Timmy": [{"class": "math", "score": 87, "year": 2014}, {"class": "english", "score": 91, "year": 2015}], 
"Sally":[{"class": "math", "score": 95, "year": 2014}]}

我需要建立一个新的学生名字字典，他们的总分萨利只有一分

输出如下所示：

new_dict = {"John": 185, "Timmy": 178, "Sally": 95}

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任何帮助或指导都将不胜感激

使用字典理解：

{k: sum(x['score'] for x in v) for k, v in my_dict.items()}

代码：

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我试图写一个程序来解决这个问题

score_dict = {}
for name in my_dict:
    score_dict[name] = 0
    class_items = my_dict[name]
    for class_item in class_items:
        score_dict[name] += class_item['score']

print score_dict

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这回答了你的问题吗？不完全是这样，问题是该值位于字典中的列表中。不幸的是，只有当它只是一个列表时，这个解决方案才有效。

score_dict = {}
for name in my_dict:
    score_dict[name] = 0
    class_items = my_dict[name]
    for class_item in class_items:
        score_dict[name] += class_item['score']

print score_dict