Python 如何使用django将Paginator添加到搜索结果中?

Python 如何使用django将Paginator添加到搜索结果中?,python,django,python-3.x,django-rest-framework,django-views,Python,Django,Python 3.x,Django Rest Framework,Django Views,您好,我想在搜索结果页面中添加分页器如何操作 我的代码: view.py: def search(request): if request.method == 'GET': query= request.GET.get('q') submitbutton= request.GET.get('submit') if query is not None: home_database= Homepage.objects.filter(Q(name__icon

您好,我想在搜索结果页面中添加分页器如何操作

我的代码:

view.py:

def search(request):
if request.method == 'GET':
    query= request.GET.get('q')
    submitbutton= request.GET.get('submit')

    if query is not None:

        home_database= Homepage.objects.filter(Q(name__icontains=query) | Q(app_contect__icontains=query) | Q(page_url__icontains=query) | Q(app_image__icontains=query))
        pcprograms_database= PCprogram.objects.filter(Q(name__icontains=query) | Q(app_contect__icontains=query) | Q(page_url__icontains=query) | Q(app_image__icontains=query))
        androidapk_database= AndroidApks.objects.filter(Q(name__icontains=query) | Q(app_contect__icontains=query) | Q(page_url__icontains=query) | Q(app_image__icontains=query))
        androidgames_database= AndroidGames.objects.filter(Q(name__icontains=query) | Q(app_contect__icontains=query) | Q(page_url__icontains=query) | Q(app_image__icontains=query))
        antiruvs_database= Antivirus.objects.filter(Q(name__icontains=query) | Q(app_contect__icontains=query) | Q(page_url__icontains=query) | Q(app_image__icontains=query))
        systems_database= OpratingSystems.objects.filter(Q(name__icontains=query) | Q(app_contect__icontains=query) | Q(page_url__icontains=query) | Q(app_image__icontains=query))
        pcgames_database= PCgames.objects.filter(Q(name__icontains=query) | Q(app_contect__icontains=query) | Q(page_url__icontains=query) | Q(app_image__icontains=query))

        results= sorted(chain(home_database,pcprograms_database,androidapk_database,androidgames_database,antiruvs_database,systems_database,pcgames_database),key=attrgetter('name'))

        paginator = Paginator(results, 2) # Show 25 rows per page
        page = request.GET.get('page')
        results = paginator.get_page(page)

        context={'results': results,
                 'submitbutton': submitbutton}

        return render(request, 'html_file/enterface.html', context)

    else:
        return render(request, 'html_file/enterface.html')

else:
    return render(request, 'html_file/enterface.html')
html页面:

     {% if submitbutton == 'Search' and request.GET.q != '' %}
 {% if results %}
 <h1> <small> Results for <b><i style="color:#337ab7">{{ request.GET.q }}</i></b></small> : </h1>
 <br/><br/>

 {% for result in results %}
 <label id="label_main_app"> <img style="margin-top:.3%;margin-left:.3%" id="img_main_app_first_screen" src="{{result.app_image.url}}" alt="no image found !" height="160" width="165" > {{result.name}} <br><br> <p id="p_size_first_page"> {{result.app_contect}} <br> <br> <a href="{{ result.page_url }}" type="button" class="btn btn-primary"><big> See More & Download </big>  </a> </p>
  </label>

 {% endfor %}

 <!–– here for moving to make new pages in search if nedded  ––>
 {% if results.has_other_pages %}
   <ul class="pagination">
     {% if results.has_previous %}
       <li><a href="?q={{ request.GET.q }}&submit=Search/search-page={{ results.previous_page_number }}">&laquo;</a></li>
     {% else %}
       <li class="disabled"><span>&laquo;</span></li>
     {% endif %}
     {% for i in results.paginator.page_range %}
       {% if results.number == i %}
         <li class="active"><span>{{ i }} <span class="sr-only">(current)</span></span></li>
       {% else %}
         <li><a href="?q={{ request.GET.q }}&submit=Search/search-page={{ i }}">{{ i }}</a></li>
       {% endif %}
     {% endfor %}
     {% if results.has_next %}
       <li><a href="?q={{ request.GET.q }}&submit=Search/search-page={{ results.next_page_number }}">&raquo;</a></li>
     {% else %}
       <li class="disabled"><span>&raquo;</span></li>
     {% endif %}
   </ul>
 {% endif %}


 {% endif %}

 {% endif %}
{%if submitbutton=='Search'和request.GET.q!=''%}
{%if结果%}
{request.GET.q}的结果:


{结果中的结果为%} {{result.name}

{{result.app_contect}

{%endfor%} {%if results.has_其他_页面%}
    {%if results.has_previous%}
  • {%else%}
  • « {%endif%} {results.paginator.page_range%} {%if results.number==i%}
  • {{i}(当前)
  • {%else%}
  • {%endif%} {%endfor%} {%if results.has_next%}
  • {%else%}
  • » {%endif%}
{%endif%} {%endif%} {%endif%}
我在django的搜索结果中添加了Paginator,好吗?我把show 2项放在第页,第页有8项

但当我在网站上搜索时,它是show2item好的


并向我显示4页我可以移动到它,但当我按第2页、第3页或第4页时,它没有显示任何原因?

Django提供了
分页器
类来执行分页,请检查此处的文档:

因此,在您的
视图.py
之后

results= list(chain(home_database,pcprograms_database,androidapk_database,androidgames_database,antiruvs_database,systems_database,pcgames_database))
你可以写

paginator = Paginator(results, 25) # Show 25 rows per page
page = request.GET.get('page')
results = paginator.get_page(page)
context={'results': results,
             'submitbutton': submitbutton}
return render(request, 'html_file/enterface.html', context)
HTML文件中的下一步:

{% if submitbutton == 'Search' and request.GET.q != '' %}
 {% if results %}
 <h1> <small> Results for {{ request.GET.q }} : </small></h1>
 <br/><br/>

 {% for result in results %}
 <label id="label_main_app"> <img style="margin-top:.3%;margin-left:.3%"  id="img_main_app_first_screen" src="{{result.app_image.url}}" alt="no image found !" height="160" width="165" > {{result.name}} <br><br> <p id="p_size_first_page"> {{result.app_contect}} <br> <br> <a href="{{ result.page_url }}" type="button" class="btn btn-primary"><big> See More & Download </big>  </a> </p>
  </label>
 {% endfor %}

 {% if results %}
 <div class="pagination">
  <span class="step-links">
    {% if results.has_previous %}
        <a href="?page=1">&laquo; first</a>
        <a href="?page={{ results.previous_page_number }}">previous</a>
    {% endif %}

    <span class="current">
        Page {{ results.number }} of {{ results.paginator.num_pages }}.
    </span>

    {% if results.has_next %}
        <a href="?page={{ results.next_page_number }}">next</a>
        <a href="?page={{ results.paginator.num_pages }}">last &raquo;</a>
    {% endif %}
    </span>
  </div>
  {% endif %}
 {% else %}
 <h3> No results for this search </h3>
 {% endif %}
 {% endif %}

您可以决定使用
公共_键
,在您的情况下,可能是字段
名称

Django提供了
分页器
类来执行分页,我在这里回答了一个类似的问题:()您也可以在这里检查文档:()我读了答案,但它对我没有帮助,我不知道你为什么要写代码,我需要在我的代码中添加什么来进行活动分页?请检查下面的答案,我希望它有帮助,否则请随意询问你的疑问。我已经尝试了你的答案,这就是发生的事,我已经在django中添加了分页器来搜索结果,好吗?我把show 2项目放在页面中,我有8个项目在页面中,但当我在网站中搜索时,它是show 2项目好的,并向我显示4个页面,我可以移动到它,但当我按第2、3或4页时,它没有显示任何原因?好的,我这样做了,我现在有一个错误,错误是当用户按“下一页”并转到下一页时,没有结果出现在第2页或第3页等…**我已经添加了8个同名应用程序,所以当我搜索时,我已经在一个页面中看到了6个,但当我按“下一步”时,没有出现应用程序,url更改为172.1.1/search/?page=2okay,,我再次尝试,但没有任何更改,它的保留不显示rest结果,我将更新我的问题,,请查看更新,并感谢您的时间
from operator import attrgetter
results = sorted(
    chain(home_database,pcprograms_database,androidapk_database, ..etc),
    key=attrgetter('common_key'))