Python 从多线程函数获取返回
我在做一个IP扫描器,可以使用多线程 运行线程后,我打印返回的值(列表) 但是这些函数在没有返回列表的情况下再次运行 当函数等于一个变量时,就会发生这种情况。 这需要更多的时间,因为函数一个接一个地运行 怎么办Python 从多线程函数获取返回,python,python-multithreading,python-3.8,Python,Python Multithreading,Python 3.8,我在做一个IP扫描器,可以使用多线程 运行线程后,我打印返回的值(列表) 但是这些函数在没有返回列表的情况下再次运行 当函数等于一个变量时,就会发生这种情况。 这需要更多的时间,因为函数一个接一个地运行 怎么办 def first_50IP() : prefix = "192.168.1." condition = "Destination host unreachable" condition2 = "Requ
def first_50IP() :
prefix = "192.168.1."
condition = "Destination host unreachable"
condition2 = "Request timed out"
list1 = []
for xxx in range(0,50) :
ip = prefix + str(xxx)
code = "ping " + ip + " -n 1 -l 1"
ping = os.popen(code).read()
#ping = subprocess.check_output(code).decode('utf-8')
if condition not in ping and condition2 not in ping:
print(G + ip)
list1.append(ip)
return list1
def second_50IP() :
prefix = "192.168.1."
condition = "Destination host unreachable"
condition2 = "Request timed out"
list2 = []
for xxx in range(50,100) :
ip = prefix + str(xxx)
code = "ping " + ip + " -n 1 -l 1"
ping = os.popen(code).read()
#ping = subprocess.check_output(code).decode('utf-8')
if condition not in ping and condition2 not in ping:
print(G + ip)
list2.append(ip)
return list2
thread1 = threading.Thread(target=first_50IP)
thread2 = threading.Thread(target=second_50IP)
thread1.start()
thread2.start()
thread1.join()
thread2.join()
print("\nResults : \n")
final_ip1 = first_50IP()
final_ip2 = second_50IP()
print(final_ip1)
print(final_ip2)
您正在运行相同的函数两次。第一次在专用线程中,然后再次在主线程中 使用此选项可避免:
with concurrent.futures.ThreadPoolExecutor(max_workers=5) as executor:
first = executor.submit(first_50IP)
second = executor.submit(second_50IP)
print("\nResults : \n")
final_ip1 = first.result()
final_ip2 = second.result()
print(final_ip1)
print(final_ip2)
旁注:您可以只使用一个函数,而不是像这样使用两个几乎相同的函数:
def ping_many(start, count) :
prefix = "192.168.1."
condition = "Destination host unreachable"
condition2 = "Request timed out"
list1 = []
for xxx in range(start, start+count) :
ip = prefix + str(xxx)
code = "ping " + ip + " -n 1 -l 1"
ping = os.popen(code).read()
#ping = subprocess.check_output(code).decode('utf-8')
if condition not in ping and condition2 not in ping:
print(G + ip)
list1.append(ip)
return list1
tasks = {}
with concurrent.futures.ThreadPoolExecutor(max_workers=5) as executor:
for start in [0, 50]:
tasks.add(executor.submit(ping_many, start, 50))
print("\nResults : \n")
for task in tasks:
print(task.result())
在这种情况下,您可以向executor提交具有不同参数的函数,如下所示:
def ping_many(start, count) :
prefix = "192.168.1."
condition = "Destination host unreachable"
condition2 = "Request timed out"
list1 = []
for xxx in range(start, start+count) :
ip = prefix + str(xxx)
code = "ping " + ip + " -n 1 -l 1"
ping = os.popen(code).read()
#ping = subprocess.check_output(code).decode('utf-8')
if condition not in ping and condition2 not in ping:
print(G + ip)
list1.append(ip)
return list1
tasks = {}
with concurrent.futures.ThreadPoolExecutor(max_workers=5) as executor:
for start in [0, 50]:
tasks.add(executor.submit(ping_many, start, 50))
print("\nResults : \n")
for task in tasks:
print(task.result())
tasks.add(executor.submit(ping\u many,start,50))中有一个错误。
dict的实例没有“add”成员如何将其添加到完整的ip范围?192.168.1.0-192.168.1.255找到方法谢谢