“为什么？”；名称错误：名称未定义"；在外部执行Python文件时发生？

我有一个多处理代码，它运行一个函数从API检索项目：

import os
import pandas as pd
from multiprocessing import Pool
from datetime import timedelta, date
from external_functions import get_api_item #separate .py file with a function

def date_range(start_date, end_date):
    for n in range(int ((end_date - start_date).days)):
        yield start_date + timedelta(n)

start_date = date(2020, 1, 29)
end_date = date(2020, 1, 30)
date_list = []

for single_date in date_range(start_date, end_date):
    date_list.append(single_date.strftime('%Y-%m-%d'))

if __name__ == '__main__':
    global results
    p = Pool(20)
    results = p.map(get_api_item, date_list)
    p.terminate()
    p.join()

result = pd.concat(results)

当我从Jupyter笔记本、Spyder等运行这段代码时，它就工作了。当我从SSIS中的

executeprocess

任务执行它时，我得到以下错误：

Traceback (most recent call last):
  File "<string>", line 1, in <module>
  File "E:\Python\Anaconda3\lib\multiprocessing\spawn.py", line 105, in spawn_ma
in
    exitcode = _main(fd)
  File "E:\Python\Anaconda3\lib\multiprocessing\spawn.py", line 114, in _main
    prepare(preparation_data)
  File "E:\Python\Anaconda3\lib\multiprocessing\spawn.py", line 225, in prepare
    _fixup_main_from_path(data['init_main_from_path'])
  File "E:\Python\Anaconda3\lib\multiprocessing\spawn.py", line 277, in _fixup_m
ain_from_path
    run_name="__mp_main__")
  File "E:\Python\Anaconda3\lib\runpy.py", line 263, in run_path
    pkg_name=pkg_name, script_name=fname)
  File "E:\Python\Anaconda3\lib\runpy.py", line 96, in _run_module_code
    mod_name, mod_spec, pkg_name, script_name)
  File "E:\Python\Anaconda3\lib\runpy.py", line 85, in _run_code
    exec(code, run_globals)
  File "<path to api>\api.py", line 29, in <module>
    result = pd.concat(results)
NameError: name 'results' is not defined

---

如果uuu name uu='\uuuuu main uuu'这一行专门检查调用文件的位置，如果您直接调用它，则名称等于main，但是如果您在服务中运行它，则名称基于调用它的任何服务。您得到一个名称错误，因为

results

仅在if语句中定义。（由于您使用的是global，因此不是范围问题）

我一直在用谷歌搜索SSIS实例的名称，但没有找到任何东西

有关

\uuuu name\uuuuu==''\uuuuuu main\uuuuu'

的更多信息：

---

这是有道理的。你会如何用谷歌最初的术语来表达？它会一直是同一个名字吗？有没有办法排除这个问题，或者不建议这样做？不幸的是，我不知道如何使用

if

语句来解决这个问题，但是关于事物如何命名的更多细节可以在以下位置找到：猜一猜，也许是uu name\uuuu==SSIS？我刚刚在谷歌上搜索了'name'，'SSIS name'，'if name='main'（所有粗体字都用_;包装，但我不知道如何使格式显示它们）

  File "E:\Python\Anaconda3\lib\multiprocessing\spawn.py", line 143, in get_prep
aration_data
    _check_not_importing_main()
  File "E:\Python\Anaconda3\lib\multiprocessing\spawn.py", line 136, in _check_n
ot_importing_main
    is not going to be frozen to produce an executable.''')
RuntimeError:
    An attempt has been made to start a new process before the
    current process has finished its bootstrapping phase.

    This probably means that you are not using fork to start your
    child processes and you have forgotten to use the proper idiom
    in the main module:

        if __name__ == '__main__':
            freeze_support()
            ...

    The "freeze_support()" line can be omitted if the program
    is not going to be frozen to produce an executable.