Python ModuleNotFoundError:没有名为'_未来'；

我应该如何解决anaconda中的打印函数

我写下面的代码

from _future_ import print_function

但它显示了一个错误，那就是

---------------------------------------------------------------------------
ModuleNotFoundError                       Traceback (most recent call last)
<ipython-input-2-fd1a0773c2f5> in <module>
----> 1 from _future_ import print_function

ModuleNotFoundError: No module named '_future_'

---------------------------------------------------------------------------
ModuleNotFoundError回溯（上次最近调用）
在里面
---->1来自u future u导入打印功能
ModuleNotFoundError:没有名为“\u future\u”的模块

---

注意：使用创建的环境作为py36创建uam。因为在我使用Python3.7的地方安装ensorflow和keras非常困难。这就是为什么我创建了一个新的环境，其中python版本是python 3.6.0

python的

\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

模块的两侧都有两个下划线，因此您

from __future__ import print_function

---

Python的

\uuuu future\uuuu

模块的两侧都有两个下划线，因此您的导入应该是：

from __future__ import print_function

---

它是

\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu；
print
语句已从Python3.0中删除。如果您使用的是Python3.6，则无论如何都不需要此特定导入-
print\u函数自3.0以来一直是默认的。该行仅在2.x版本上需要。我是否应该在代码中避免使用该语句？它是
\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu；
print
语句已从Python3.0中删除。如果您使用的是Python3.6，则无论如何都不需要此特定导入-
print\u函数自3.0以来一直是默认的。该行仅在2.x版本上才需要。我应该避免在代码中使用此语句吗？非常感谢兄弟们！非常感谢兄弟们！