Python 转换烧瓶。响应请求。响应
我正在编写一些测试,我想将flask.Response对象转换为相应的requests.Response对象。因此,我有两个Flask应用程序(例如Python 转换烧瓶。响应请求。响应,python,unit-testing,flask,mocking,python-requests,Python,Unit Testing,Flask,Mocking,Python Requests,我正在编写一些测试,我想将flask.Response对象转换为相应的requests.Response对象。因此,我有两个Flask应用程序(例如A和B),并且A对B进行内部调用(通过请求.post(url,json=payload))。我的目标是在不启动任何服务器的情况下正确模拟这些调用,当前的解决方案如下所示: from unittest import mock ... def mock_B_request(url, json): response = app_B.test_c
A
和B
),并且A
对B
进行内部调用(通过请求.post(url,json=payload)
)。我的目标是在不启动任何服务器的情况下正确模拟这些调用,当前的解决方案如下所示:
from unittest import mock
...
def mock_B_request(url, json):
response = app_B.test_client().post(url, json=json) # flask.Response
# Some hacking should be done here,
# since flask.Respone doesn't have `.ok`, `.json()`, etc.,
# so it will break the code inside app_A
return response
...
# Inside the actual test method
with mock.patch('requests.post', side_effect=mock_B_request):
response = app_A.test_client().post(url, json=payload)
result = response.get_json()
...
有没有人遇到过这样的问题?这里最简单的解决方案是什么?最终,我找到了一个非常简单的解决方案:
def mock_B_request(url, **kwargs):
response = app_B.test_client().post(url, json=kwargs['json'])
# Hack a bit in order to make flask.Response
# support the same API as requests.Response
response_mock = mock.MagicMock()
response.status_code = response.status_code
response_mock.ok = response.status_code == 200
response_mock.json = lambda: response.get_json()
return response_mock
我希望这对某人有帮助