如何使用Python创建windows服务

如何使用Python创建windows服务,python,windows-services,pywin32,Python,Windows Services,Pywin32,我已经编写了一个python脚本,它将作为windows服务安装在中。代码如下: import datetime import logging from logging.handlers import RotatingFileHandler import os import time from random import randint import win32serviceutil import win32service import win32event import servicemana

我已经编写了一个python脚本,它将作为windows服务安装在中。代码如下:

import datetime
import logging
from logging.handlers import RotatingFileHandler
import os
import time
from random import randint
import win32serviceutil
import win32service
import win32event
import servicemanager
import socket


def setup_logger(logger_name, log_file, level=logging.ERROR):
    log_formatter = logging.Formatter('%(asctime)s %(message)s')
    my_handler = RotatingFileHandler(log_file, maxBytes=100 * 1024 * 1024, backupCount=5)
    my_handler.setFormatter(log_formatter)
    my_handler.setLevel(level)
    l = logging.getLogger(logger_name)
    l.handlers[:] = []
    l.addHandler(my_handler)


curr_path = os.getcwd()
log_file = "F:\\Projects\\TestService\\logs\\application.log"
setup_logger('debug', log_file)
log = logging.getLogger('debug')

class AppServerSvc(win32serviceutil.ServiceFramework):
    _svc_name_ = "test_service"
    _svc_display_name_ = "Test Service"

    def __init__(self, args):
        win32serviceutil.ServiceFramework.__init__(self, args)
        self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
        socket.setdefaulttimeout(60)
        self.isrunning = False

    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        win32event.SetEvent(self.hWaitStop)
        self.isrunning = False

    def SvcDoRun(self):
        servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,
                              servicemanager.PYS_SERVICE_STARTED,
                              (self._svc_name_, ''))
        self.isrunning = True
        self.main()

    def main(self):
        while self.isrunning:
            log.error("Running {}".format(randint(00, 99)))
            time.sleep(10)


if __name__ == '__main__':
    win32serviceutil.HandleCommandLine(AppServerSvc)
我已经运行了命令
python test\u service.py install
来安装服务,并获得了正确的输出
Installing service test\u service installed
。当我打开“服务”选项卡时,我可以看到我的服务列在那里。当我单击“启动服务”时,我发现以下错误:

谁能告诉我代码中有什么错误导致它不能启动服务。请帮忙。谢谢

更新:

我在
cmd
的调试模式下运行了该服务,看起来它工作正常。但从“服务”选项卡上看,它不起作用,并显示上述错误

> python test_service.py debug
      Debugging service test_service - press Ctrl+C to stop.
      Info 0x40001002 - The test_service service has started.
启动服务时,会出现相同的错误:

> python test_service.py start
     Starting service test_service
     Error starting service: The service did not respond to the start or control request in a timely fashion.

不确定为什么它没有运行,并且在调试模式下运行良好。请帮助。

任何面临此问题的人,只需复制
pywintypes36.dll

Python36\Lib\site packages\pywin32\u system32

Python36\Lib\site packages\win32

有用的命令:

  • 安装服务:
    python app.py安装

  • 卸载服务:
    python app.py remove

  • 启动服务:
    python app.py Start

  • 更新服务:
    python app.py更新


  • 嗨,你看到了吗?@CarloZanocco是的,我看到了,我所有的代码都是用这个答案写的。但不管怎样,我已经找到了解决方案嗨,你能分享一下解决方案吗,我也面临着类似的问题吗?@Sripalavi我已经回答了