Python Else语句语法错误（简单计算器）

我目前正在尝试编写一个小计算器，因为我正在学习python。我的问题是，它在结尾的else语句中不断输出语法错误，因为我还是初学者，我不知道为什么

您缺少一个冒号：with else

应该是：{你的逻辑}

更新：实际上你有冒号，但有条件。这应该是一个elif，而不是其他

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将last else更改为elif，如果没有默认检查，则不一定需要else。

您的代码实际上存在一些问题

不能在字符串和整数等之间进行转换。4+5不是9，而是45，因为它是两个字符串的组合。但是如果你做int4+int5，那么你会得到9

执行else语句时，不存在任何条件

因此，基本的if，elif，else是：

a = "yay"
if a == "yay":
    print("a likes you")
elif a == "no":
    print("a doesn't like you")
else:
    print("a doesn't want to respond")

Python 2.7

Python 3.6

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这里需要另一份elif声明。else之后，无法检查其他条件，因此else。我将else更改为elif，但它仍然输出无效语法并将elif标记为红色。请将代码作为文本而不是图像包含。最后一行似乎是额外的缩进级别。将它备份一个等级，并将最后一个其他等级更改为elif，它应该会工作。

print ("Welcome to your friendly Python calculator.  Use + for addition and - for substraction")
print ("This code uses period (.) for decmimals")

first = "Please enter your first number "
second = "Please enter your second number "

operator = raw_input("Please choose an operation (+ or -) ")
if operator == "+":
    num1 = input(first)
    num2 = input(second)
    print ("Result: " + str(num1 + num2))
elif operator == "-":
    num1 = input(first)
    num2 = input(second)
    print ("Result: " + str(num1 - num2))
else:
    print("You didn't enter a valid operator.")

print ("Welcome to your friendly Python calculator.  Use + for addition and - for substraction")
print ("This code uses period (.) for decmimals")

first = "Please enter your first number "
second = "Please enter your second number "

operator = input("Please choose an operation (+ or -) ")
if operator == "+":
    num1 = int(input(first))
    num2 = int(input(second))
    print ("Result: " + str(num1 + num2))
elif operator == "-":
    num1 = int(input(first))
    num2 = int(input(second))
    print ("Result: " + str(num1 - num2))
else:
    print("You didn't enter a valid operator.")