如何在两个不同的python脚本之间传递变量

我试图在两个不同的python脚本之间传递信息。它们相当长，因此为了简化起见，这里有两个我遇到相同问题的其他脚本：

a、 派克

b、 派克

我被要求输入num和tipe两次，然后第二次的条目被打印11次

如何使a.py中的变量/文件传递到b.py，在b.py中编辑/操作/操作，然后在a.py中传递回/关闭

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另外，为什么我要两次输入num和tipe，然后ifname='main'：下的代码运行？

在Python脚本之间传递变量时，请记住，调用脚本时，调用脚本可以访问被调用脚本的命名空间

也就是说，您可以尝试一下：用代码启动被调用的脚本

from __main__ import *

---

这将授予对调用方脚本的命名空间（变量和函数）的访问权。由于这些文件实际上并不是您之前所说的您将要处理的文件，我将把它留给您来应用于真正的文件，希望这能有所帮助

在Python脚本之间传递变量时，请记住，调用脚本时，调用脚本可以访问被调用脚本的命名空间

也就是说，您可以尝试一下：用代码启动被调用的脚本

from __main__ import *

---

这将授予对调用方脚本的命名空间（变量和函数）的访问权。由于这些文件实际上并不是您之前所说的您将要处理的文件，我将把它留给您来应用于真正的文件，希望这能有所帮助

您可以通过函数传递它们

a.py

f = open('test.txt', 'w+')
num = int(raw_input('How many are there: '))
tipe = raw_input('What kind are they: ')

if __name__ == '__main__':
    from b import fxn

    for x in xrange(num, num+11):
        fxn(num, tipe, f) # Pass parameters num, tipe and file handle
        num = x

    f.close()

# from a import num, tipe --> **This is not required**

# receive inputs
def fxn(num, tipe, f): 
    print num, tipe
    f.writelines(str(num)+', '+tipe)

x=5
print x 

import a
print a.x

b.py

f = open('test.txt', 'w+')
num = int(raw_input('How many are there: '))
tipe = raw_input('What kind are they: ')

if __name__ == '__main__':
    from b import fxn

    for x in xrange(num, num+11):
        fxn(num, tipe, f) # Pass parameters num, tipe and file handle
        num = x

    f.close()

# from a import num, tipe --> **This is not required**

# receive inputs
def fxn(num, tipe, f): 
    print num, tipe
    f.writelines(str(num)+', '+tipe)

x=5
print x 

import a
print a.x

执行a.py将导致

3 fruits
3 fruits
4 fruits
5 fruits
6 fruits
7 fruits
8 fruits
9 fruits
10 fruits
11 fruits
12 fruits

3水果打印两次，因为您首先调用函数，然后增加num（通过重新分配）。相反，您可以将a.py如下所示，只打印一次3种水果：

f = open('test.txt', 'w+')
num = int(raw_input('How many are there: '))
tipe = raw_input('What kind are they: ')

if __name__ == '__main__':
    from b import fxn

    for x in xrange(num, num+11):
        fxn(x, tipe, f) # Pass parameters num, tipe and file handle

    f.close()

---

您可以通过函数传递它们

a.py

f = open('test.txt', 'w+')
num = int(raw_input('How many are there: '))
tipe = raw_input('What kind are they: ')

if __name__ == '__main__':
    from b import fxn

    for x in xrange(num, num+11):
        fxn(num, tipe, f) # Pass parameters num, tipe and file handle
        num = x

    f.close()

# from a import num, tipe --> **This is not required**

# receive inputs
def fxn(num, tipe, f): 
    print num, tipe
    f.writelines(str(num)+', '+tipe)

x=5
print x 

import a
print a.x

b.py

f = open('test.txt', 'w+')
num = int(raw_input('How many are there: '))
tipe = raw_input('What kind are they: ')

if __name__ == '__main__':
    from b import fxn

    for x in xrange(num, num+11):
        fxn(num, tipe, f) # Pass parameters num, tipe and file handle
        num = x

    f.close()

# from a import num, tipe --> **This is not required**

# receive inputs
def fxn(num, tipe, f): 
    print num, tipe
    f.writelines(str(num)+', '+tipe)

x=5
print x 

import a
print a.x

执行a.py将导致

3 fruits
3 fruits
4 fruits
5 fruits
6 fruits
7 fruits
8 fruits
9 fruits
10 fruits
11 fruits
12 fruits

3水果打印两次，因为您首先调用函数，然后增加num（通过重新分配）。相反，您可以将a.py如下所示，只打印一次3种水果：

f = open('test.txt', 'w+')
num = int(raw_input('How many are there: '))
tipe = raw_input('What kind are they: ')

if __name__ == '__main__':
    from b import fxn

    for x in xrange(num, num+11):
        fxn(x, tipe, f) # Pass parameters num, tipe and file handle

    f.close()

你可以用这种方式

a.py

f = open('test.txt', 'w+')
num = int(raw_input('How many are there: '))
tipe = raw_input('What kind are they: ')

if __name__ == '__main__':
    from b import fxn

    for x in xrange(num, num+11):
        fxn(num, tipe, f) # Pass parameters num, tipe and file handle
        num = x

    f.close()

# from a import num, tipe --> **This is not required**

# receive inputs
def fxn(num, tipe, f): 
    print num, tipe
    f.writelines(str(num)+', '+tipe)

x=5
print x 

import a
print a.x

b.py

f = open('test.txt', 'w+')
num = int(raw_input('How many are there: '))
tipe = raw_input('What kind are they: ')

if __name__ == '__main__':
    from b import fxn

    for x in xrange(num, num+11):
        fxn(num, tipe, f) # Pass parameters num, tipe and file handle
        num = x

    f.close()

# from a import num, tipe --> **This is not required**

# receive inputs
def fxn(num, tipe, f): 
    print num, tipe
    f.writelines(str(num)+', '+tipe)

x=5
print x 

import a
print a.x

你可以用这种方式

a.py

f = open('test.txt', 'w+')
num = int(raw_input('How many are there: '))
tipe = raw_input('What kind are they: ')

if __name__ == '__main__':
    from b import fxn

    for x in xrange(num, num+11):
        fxn(num, tipe, f) # Pass parameters num, tipe and file handle
        num = x

    f.close()

# from a import num, tipe --> **This is not required**

# receive inputs
def fxn(num, tipe, f): 
    print num, tipe
    f.writelines(str(num)+', '+tipe)

x=5
print x 

import a
print a.x

b.py

f = open('test.txt', 'w+')
num = int(raw_input('How many are there: '))
tipe = raw_input('What kind are they: ')

if __name__ == '__main__':
    from b import fxn

    for x in xrange(num, num+11):
        fxn(num, tipe, f) # Pass parameters num, tipe and file handle
        num = x

    f.close()

# from a import num, tipe --> **This is not required**

# receive inputs
def fxn(num, tipe, f): 
    print num, tipe
    f.writelines(str(num)+', '+tipe)

x=5
print x 

import a
print a.x

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函数可以接受参数。要求您输入两次的原因是这些IO操作在全局范围内，每次导入a时都会执行。函数可以获取参数。要求您两次输入的原因是，这些IO操作在全局范围内，每次导入时都会执行。