如何在Python中将字符串列表转换为整数列表?
如果我有一个二进制文件列表如何在Python中将字符串列表转换为整数列表?,python,string,list,binary,integer,Python,String,List,Binary,Integer,如果我有一个二进制文件列表 a=['0b11001000', '0b01001100', '0b00111100', '0b00011111', '0b11110000', '0b01011010', '0b10010110', '0b00011110'] 我想将所有字符串元素转换为整数,并将其很好地放回二进制列表中: a=[0b11001000, 0b01001100, 0b00111100, 0b00011111, 0b11110000, 0b01011010, 0b100
a=['0b11001000', '0b01001100', '0b00111100', '0b00011111',
'0b11110000', '0b01011010', '0b10010110', '0b00011110']
我想将所有字符串元素转换为整数,并将其很好地放回二进制列表中:
a=[0b11001000, 0b01001100, 0b00111100, 0b00011111,
0b11110000, 0b01011010, 0b10010110, 0b00011110]
我该怎么办?试试看:
a = [int(x, 2) for x in a]
a = [int(x, 2) for x in a]
尝试一下:
a = [int(x, 2) for x in a]
a = [int(x, 2) for x in a]
将
int
与基数2一起使用:
>>> a=['0b11001000', '0b01001100', '0b00111100', '0b00011111',
... '0b11110000', '0b01011010', '0b10010110', '0b00011110']
>>> [int(x, 2) for x in a]
[200, 76, 60, 31, 240, 90, 150, 30]
将
int
与基数2一起使用:
>>> a=['0b11001000', '0b01001100', '0b00111100', '0b00011111',
... '0b11110000', '0b01011010', '0b10010110', '0b00011110']
>>> [int(x, 2) for x in a]
[200, 76, 60, 31, 240, 90, 150, 30]
尽管在第二个列表中,您将整数表示为二进制,但它们仍然是
int
类型。但是,您可以转换字符串:
尽管在第二个列表中,您将整数表示为二进制,但它们仍然是
int
类型。但是,您可以转换字符串: