Python Arduino忽略第一条消息,只响应后续消息
我使用下面的代码使用PySerial与Arduino通信Python Arduino忽略第一条消息,只响应后续消息,python,arduino,serial-port,pyserial,Python,Arduino,Serial Port,Pyserial,我使用下面的代码使用PySerial与Arduino通信 def test_without_thread(port, msg): ser = serial.Serial(port, baudrate=115200, timeout=1.) for i in range(10): ser.write(msg) print i, ser.readline().strip("\r\n") 和你一起跑的时候 msg = "q02i15i21" port
def test_without_thread(port, msg):
ser = serial.Serial(port, baudrate=115200, timeout=1.)
for i in range(10):
ser.write(msg)
print i, ser.readline().strip("\r\n")
和你一起跑的时候
msg = "q02i15i21"
port = "/dev/ttyACM1"
test_without_thread(port, msg)
提供以下输出:
0
1 oi1+1023003+i2+103+
2 oi1+1023003+i2+103+
3 oi1+1023003+i2+103+
4 oi1+1023003+i2+103+
5 oi1+1023003+i2+103+
6 oi1+1023003+i2+103+
7 oi1+1023003+i2+103+
8 oi1+1023003+i2+103+
9 oi1+1023003+i2+103+
如果我在第一次写入之前睡觉(就在循环之前),所有请求都会超时。在我的Arduino代码中的serial.Begin()
之后,我确实睡了10毫秒
我的Arduino代码(相关部分)如下:
volatile unsigned int interlock_state = OPEN;
float get_ext_ilk(){
return (float) interlock_state;
}
void dummyFunc(float set_value){
Serial.println("Called the dummy function!");
}
void setup() {
Serial.begin(115200);
delay(10);
com.add_channel(mist1::Channel("EXT_ILK", 'x', 1, &dummyFunc, &get_ext_ilk)); //To read interlock status
}
void loop() {
if (Serial.available()) {
com.respond_to_input_message();
}
}
void mist1::Communication::respond_to_input_message() {
char inputMessage[128];
get_serial_data(inputMessage);
char keyword = inputMessage[0];
if (keyword == 'c') {
Serial.println(get_all_channel_names());
} else if (keyword == 'i') {
Serial.println(get_all_channel_identifiers());
} else if (keyword == 'n') {
Serial.println(_com_name);
} else if (keyword == 'q') {
// Query.
// Find what the user is querying for.
int numberOfChannels = get_number_of_channels_queried(inputMessage);
// Read input message.
unsigned precisions[numberOfChannels];
char channelIdentifiers[numberOfChannels];
unsigned channelNumbers[numberOfChannels];
String messageToReturn = "o";
for (unsigned channelIndex = 0; channelIndex < numberOfChannels; channelIndex++) {
for (unsigned i=0; i < _number_of_channels; i++) {
if ((char)_all_channels[i].get_channel_identifier() == channelIdentifiers[channelIndex]){
if (_all_channels[i].get_channel_number() == channelNumbers[channelIndex]){
float valueToOutput = _all_channels[i].call_get_func();
char * buff = float2s(valueToOutput, precisions[channelIndex]);
char valueToPrint[1 + 1 + precisions[channelIndex] + 1 + 1 + 1]; // sign(1) + digit(1) + precision + exponent(1) + sign(1) + termination character(1).
memset(valueToPrint, '\0', (1 + 1 + precisions[channelIndex] + 1 + 1 + 1));
convert_scientific_notation_to_mist1(buff, valueToPrint, precisions[channelIndex]);
String new_addition = (String) channelIdentifiers[channelIndex] + (String) channelNumbers[channelIndex] + valueToPrint;
messageToReturn += new_addition;
break;
}
}
}
}
messageToReturn += "\r\n";
Serial.print(messageToReturn);
}
respond\u to\u input\u message()
方法如下:
volatile unsigned int interlock_state = OPEN;
float get_ext_ilk(){
return (float) interlock_state;
}
void dummyFunc(float set_value){
Serial.println("Called the dummy function!");
}
void setup() {
Serial.begin(115200);
delay(10);
com.add_channel(mist1::Channel("EXT_ILK", 'x', 1, &dummyFunc, &get_ext_ilk)); //To read interlock status
}
void loop() {
if (Serial.available()) {
com.respond_to_input_message();
}
}
void mist1::Communication::respond_to_input_message() {
char inputMessage[128];
get_serial_data(inputMessage);
char keyword = inputMessage[0];
if (keyword == 'c') {
Serial.println(get_all_channel_names());
} else if (keyword == 'i') {
Serial.println(get_all_channel_identifiers());
} else if (keyword == 'n') {
Serial.println(_com_name);
} else if (keyword == 'q') {
// Query.
// Find what the user is querying for.
int numberOfChannels = get_number_of_channels_queried(inputMessage);
// Read input message.
unsigned precisions[numberOfChannels];
char channelIdentifiers[numberOfChannels];
unsigned channelNumbers[numberOfChannels];
String messageToReturn = "o";
for (unsigned channelIndex = 0; channelIndex < numberOfChannels; channelIndex++) {
for (unsigned i=0; i < _number_of_channels; i++) {
if ((char)_all_channels[i].get_channel_identifier() == channelIdentifiers[channelIndex]){
if (_all_channels[i].get_channel_number() == channelNumbers[channelIndex]){
float valueToOutput = _all_channels[i].call_get_func();
char * buff = float2s(valueToOutput, precisions[channelIndex]);
char valueToPrint[1 + 1 + precisions[channelIndex] + 1 + 1 + 1]; // sign(1) + digit(1) + precision + exponent(1) + sign(1) + termination character(1).
memset(valueToPrint, '\0', (1 + 1 + precisions[channelIndex] + 1 + 1 + 1));
convert_scientific_notation_to_mist1(buff, valueToPrint, precisions[channelIndex]);
String new_addition = (String) channelIdentifiers[channelIndex] + (String) channelNumbers[channelIndex] + valueToPrint;
messageToReturn += new_addition;
break;
}
}
}
}
messageToReturn += "\r\n";
Serial.print(messageToReturn);
}
void mist1::通信::响应输入消息(){
字符输入消息[128];
获取串行数据(输入消息);
char关键字=输入消息[0];
如果(关键字=='c'){
Serial.println(获取所有通道名称());
}else if(关键字=='i'){
Serial.println(获取所有通道标识符());
}else if(关键字='n'){
Serial.println(_com_name);
}else if(关键字=='q'){
//询问。
//查找用户正在查询的内容。
int numberOfChannels=获取所查询通道的数量(inputMessage);
//读取输入消息。
无符号精度[通道数];
字符通道标识符[numberOfChannels];
无符号信道号[信道数];
字符串messageToReturn=“o”;
for(无符号channelIndex=0;channelIndex
我已经用多个Arduinos、电缆和USB端口进行了测试
这是怎么回事?为什么Arduino会忽略第一条消息,而只对后续消息做出响应?当您打开Arduino序列时,它会重新启动。因此,您必须等待重新启动结束(睡眠2秒)。在此期间写入的所有内容都将丢失 请注意,重新启动完成后,串行缓冲区中可能有垃圾 在你的函数
respond\u to\u input\u message()
我看不到响应如果消息无法识别,你应该有一个调试响应
我提到了我遇到的最后一个问题;对于我的(中文=CH340 USB/串行)nano,我无法可靠地使用比pySerial更高的9600波特的速度
祝你好运。idk,但我经常在串行端口代码中看到“一次性”的第一项……一次性的第一项是什么?就像在我们不关心的消息中一样?没错。空的是常见的。