Python 如果陈述被卡住，主谋娱乐

我正在重新制作《智囊团》游戏，我被一些“如果”的说法所困扰 我试图让它告诉用户，如果颜色与

guess1

中的颜色不一样，但正确的颜色是

guess2

它将

打印“guess1正确颜色错误位置”

PythonV-2.7.8

colors =  ('R','B','G','P','Y','O')
Color1 = random.choice(colors)
Color2 = random.choice(colors)
Color3 = random.choice(colors)
Color4 = random.choice(colors)
guess1 = raw_input("First Color: ") 
guess2 = raw_input("Second Color: ")
guess3 = raw_input("Third Color: ")
guess4 = raw_input("Fourth Color: ")
guesses = (guess1,guess2,guess3,guess4)
Allcolors = (Color1,Color2,Color3,Color4)

if guesses == Allcolors:
        print "All colors are correct!"
    if guesses != Allcolors:
####
        if guess1 == Color2 or Color3 or Color4:
            print "Guess 1 right color wrong position"
        if guess1 == Color1:
            print "Color 1 is correct"
####
        if guess2 == Color2:
            print "Color 2 is correct"
        if guess3 == Color3:
            print "Color 3 is correct"
        if guess4 == Color4:
            print "Color 4 is correct"

这不管用。您必须重复该变量：

if guess1 == Color2 or guess1 == Color3 or guess1 == Color4:

您还可以在操作符中使用

，查看容器：

if guess1 in (Color2, Color3, Color4):

此处的缩进是否与本地代码的缩进相同？如果是这样的话，看看你怎么永远不会同时拥有
猜测==Allcolors
和
猜测！=所有颜色
if guess1 in (Color2, Color3, Color4):