从Python中的文本文件读入多层次、复杂的词典？
我得到一个文本文件，其中包含一个多级python字典的打印输出。将其作为“字典中的字典”加载回Python的简单方法是什么，以保留层次结构从Python中的文本文件读入多层次、复杂的词典？,python,Python,我得到一个文本文件，其中包含一个多级python字典的打印输出。将其作为“字典中的字典”加载回Python的简单方法是什么，以保留层次结构 {"options":{"version":2,"background":{"enable":"color","enableVR":false,"uid":"51af6a870cce449eb75b0345feebaebb","color":[0.06666666666666667,0.06666666666666667,0.0666666666666666
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我正在考虑基于规则的解析，但这会非常复杂 首先将文件内容读入字符串，如：
with open("thefile") as f:
s = f.read()
eval（）thedict = eval(s)
false, true = 0, 1
因为
falsetruewith open("thefile") as f:
s = f.read()
eval（）thedict = eval(s)
false, true = 0, 1
因为
falsetrue'filename'myJSON>>> myJSON['options']['version']
2
在这种情况下，最好的方法是将字符串加载到JSON解析器中。这将返回您需要的对象。请使用以下代码（其中
'filename'myJSON>>> myJSON['options']['version']
2
你那里的东西看起来像JSON，不是吗？您是否尝试过使用？
导入json；d=“”；myd=json.loads（d）导入json；d=“”；myd=json.loads（d）falsetruefalsetruefalsetruefalsetrue和snake\u case\uugenerateDatagenerateData\u useModelgenerateData\u-useModelgenerateData\u-useModel和snake\u case\uugenerateDatagenerateData\u useModelgenerateData\u-useModelgenerateData\u-useModel