Python Numpy重塑/重新打包?
假设我有一个2 x 8 x 3的数组,如下所示:Python Numpy重塑/重新打包?,python,numpy,Python,Numpy,假设我有一个2 x 8 x 3的数组,如下所示: array([[[ 0, 1, 2], [ 1, 2, 3], [ 2, 3, 4], [ 3, 4, 5], [ 4, 5, 6], [ 5, 6, 7], [ 6, 7, 8], [ 7, 8, 9]], [[10, 11, 12], [11, 12, 13], [12, 13, 14], [13, 14, 15],
array([[[ 0, 1, 2],
[ 1, 2, 3],
[ 2, 3, 4],
[ 3, 4, 5],
[ 4, 5, 6],
[ 5, 6, 7],
[ 6, 7, 8],
[ 7, 8, 9]],
[[10, 11, 12],
[11, 12, 13],
[12, 13, 14],
[13, 14, 15],
[14, 15, 16],
[15, 16, 17],
[16, 17, 18],
[17, 18, 19]]])
我如何重塑它,使其成为一个8 x 2 x 3的阵列,其中包含以下元素:
[[[ 0, 1, 2],
[10, 11, 12]],
[[ 1, 2, 3],
[11, 12, 13]],
...
重塑(8,2,3)
给出了以下结果,这不是我想要的:
array([[[ 0, 1, 2],
[ 1, 2, 3]],
[[ 2, 3, 4],
[ 3, 4, 5]],
[[ 4, 5, 6],
[ 5, 6, 7]],
[[ 6, 7, 8],
[ 7, 8, 9]],
[[10, 11, 12],
[11, 12, 13]],
[[12, 13, 14],
[13, 14, 15]],
[[14, 15, 16],
[15, 16, 17]],
[[16, 17, 18],
[17, 18, 19]]])
如果它适用于一般的第二维度(不仅仅是m=2),则更好。谢谢大家! 交换前两个轴
np.swapaxes(a,0,1)
np.swapaxes(a,0,1)
Yes!上帝,这么简单:)想写一个答案,这样我就可以开始了吗?