Python 使用列表获得平均值

该程序应要求用户输入12个月的月降雨量，计算并合计该年的降雨量、月平均降雨量以及降雨量最高和最低的月份

我可以让它要求输入，给出年度总数和每月平均数，但我觉得该计划的输入部分应该以某种方式减少，它看起来太大太笨重，我不太明白如何获得高/低平均数。 任何帮助都将不胜感激。 提前谢谢

def main():
    jan = int(input('Enter Rainfall For January: '))
    feb = int(input('Enter Rainfall for February: '))
    mar = int(input('Enter Rainfall For March: '))
    april = int(input('Enter Rainfall For April: '))
    may = int(input('Enter Rainfall For May: '))
    june = int(input('Enter Rainfall For June: '))
    jul = int(input('Enter Rainfall For July: '))
    aug = int(input('Enter Rainfall For August: '))
    sept = int(input('Enter Rainfall For September: '))
    oct = int(input('Enter Rainfall For October: '))
    nov = int(input('Enter Rainfall For November: '))
    dec = int(input('Enter Rainfall For Deceember: '))
    totalyear = jan + feb + mar + april + may + june + jul + aug + sept + oct + nov + dec
    print('The total for the year is: ',totalyear)
    avg = jan + feb + mar + april + may + june + jul + aug + sept + oct + nov + dec / 12
    print('The average monthly rainfall is: ',avg)
main()

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您可以使用列表和循环：

def main():
    months = ["Jan","Feb" .... ,"Dec"]
    rain = []
    for month in months:
        rain.append(int(input("Enter .. for" + month)))
    print("Total", sum(rain))
    print("Average", sum(rain)/float(len(rain)))

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类似地，对于最大值和最小值，您可以使用maxrain和minrain。

您可以使用列表和循环：

def main():
    months = ["Jan","Feb" .... ,"Dec"]
    rain = []
    for month in months:
        rain.append(int(input("Enter .. for" + month)))
    print("Total", sum(rain))
    print("Average", sum(rain)/float(len(rain)))

同样，对于最大值和最小值，可以使用maxrain和minrain