Python 函数参数中的动态变量
我尝试使用var的名称动态调用函数,但我不知道这是否可行,比如:Python 函数参数中的动态变量,python,list,Python,List,我尝试使用var的名称动态调用函数,但我不知道这是否可行,比如: fight_movies = list() # var how I want to use in function call win_movies = list() # var how I want to use in function call knowledge_movies = list() # var how I want to use in function call biography_movies = list()
fight_movies = list() # var how I want to use in function call
win_movies = list() # var how I want to use in function call
knowledge_movies = list() # var how I want to use in function call
biography_movies = list() # var how I want to use in function call
for genre in genres:
.... Ommited #\/\/\/\/\/\/ Here is where I call the function
write_jsonl(genre + '_movies', genre, rating, title, genre) #here is the call of the function
def write_jsonl(movie_list, genre, rating, title, json_name):
dict = {'title': title, 'genre': genre, 'rating': rating}
movie_list.append(dict)
# print(action_movies)
with jsonlines.open(json_name+'.jsonl', mode='w') as writer:
writer.write(movie_list)
我试图以列表的形式动态传递变量名,但我不确定在python中是否可行,有什么建议吗
Error: Traceback (most recent call last):
File "bucky.py", line 58, in <module>
web_crawling()
File "bucky.py", line 34, in web_crawling
write_jsonl(genre + '_movies', genre, rating, title, genre)
File "bucky.py", line 52, in write_jsonl
movie_list.append(dict)
AttributeError: 'str' object has no attribute 'append'
错误:回溯(最近一次呼叫最后一次):
文件“bucky.py”,第58行,在
网络爬网
文件“bucky.py”,第34行,在web_爬行中
写作(体裁+电影、体裁、评级、标题、体裁)
文件“bucky.py”,第52行,在write_jsonl中
电影列表。附加(dict)
AttributeError:“str”对象没有属性“append”
您可以在/like中找到您的变量
正如大多数人所建议的那样,使用字典,然后如果你想,我认为你打算让它做的是,然后将字典存储在一个列表中。然而,您的代码显示了一个问题,您传递了一个字符串,我相信您打算将其作为一个列表
def write_jsonl(movie_list, genre, rating, title, json_name):
d= {'title': title, 'genre': genre, 'rating': rating}
movie_list.append(d) #<-- movie_list based on your traceback is a str
# print(action_movies)
with jsonlines.open(json_name+'.jsonl', mode='w') as writer:
writer.write(movie_list)
更好的方法是在字典中按类型存储标题列表,您可以使用Python标准库中的defaultdict
数据模型来实现这一点
from collections import defaultdict
movie_list = defaultdict(list)
def write_jsonl(movie_list, genre, rating, title, json_name):
d= {'title': title, 'genre': genre, 'rating': rating}
movie_list['{}_movies'.format(genre)].append(d)
# print(action_movies)
with jsonlines.open(json_name+'.jsonl', mode='w') as writer:
writer.write(movie_list)
movie_list
>>defaultdict(list,
{'Crime_movies': [{'title': 'Godfather',
'genre': 'Crime',
'rating': '10'}]})
movie_list['Crime_movies']
>>[{'title': 'Godfather', 'genre': 'Crime', 'rating': '10'}]
也不要使用内置方法或保留名称作为变量,我将您的dict
变量替换为justd
只需使用字典即可:
genres_dict = {k: [] for k in ('fight', 'win', 'knowledge', 'biography')}
for genre in genres:
write_jsonl(genres_dict[genre], genre, rating, title, genre)
不建议使用可变数量的变量
相关:。不要这样做。使用字典。是的,你是对的,菲利普·姆林纳斯基,但我相信他试图做的是动态地传递这个函数,这样他就不必多次调用函数,为每种类型创建多个ifs
from collections import defaultdict
movie_list = defaultdict(list)
def write_jsonl(movie_list, genre, rating, title, json_name):
d= {'title': title, 'genre': genre, 'rating': rating}
movie_list['{}_movies'.format(genre)].append(d)
# print(action_movies)
with jsonlines.open(json_name+'.jsonl', mode='w') as writer:
writer.write(movie_list)
movie_list
>>defaultdict(list,
{'Crime_movies': [{'title': 'Godfather',
'genre': 'Crime',
'rating': '10'}]})
movie_list['Crime_movies']
>>[{'title': 'Godfather', 'genre': 'Crime', 'rating': '10'}]
genres_dict = {k: [] for k in ('fight', 'win', 'knowledge', 'biography')}
for genre in genres:
write_jsonl(genres_dict[genre], genre, rating, title, genre)