Python-使用模式匹配目录（正则表达式）

我编写了一个循环，它忽略了其中包含.txt文件的所有子目录

src = raw_input("Enter source disk location: ")
src = os.path.abspath(src)
dst = raw_input("Enter first destination to copy: ")
dst = os.path.abspath(dst)
dest = raw_input("Enter second destination to move : ")
dest = os.path.abspath(dest) 

path_patter = '(\S+)_(\d+)_(\d+)_(\d+)__(\d+)_(\d+)_(\d+)'

for dir, dirs, files in os.walk(src):
if any(f.endswith('.txt') for f in files):
    dirs[:] = []  # do not recurse into subdirectories
    continue  
files = [os.path.join(dir, f) for f in files ]

for f in files:

    part1 = os.path.dirname(f)
    part2 = os.path.dirname(os.path.dirname(part1))
    part3 = os.path.split(part1)[1]
    path_miss1 = os.path.join(dst, "missing_txt")
    path_miss = os.path.join(path_miss1, part3)
    path_missing = os.path.join(dest, "missing_txt")
    searchFileName = re.search(path_patter, part3)#### update

    if searchFileName:#####update
    try:
        if not os.path.exists(path_miss):
            os.makedirs(path_miss)
        else:
            pass

        if os.path.exists(path_miss):
            distutils.dir_util.copy_tree(part1, path_miss)
        else:
            debug_status += "missing_file\n"
            pass

        if (get_size(path_miss)) == 0:
            os.rmdir(path_miss)
        else:
            pass

        if not os.path.exists(path_missing):
            os.makedirs(path_missing)
        else:
            pass

        if os.path.exists(path_missing):
            shutil.move(part1, path_missing)
        else:
            pass

        if (get_size(path_missing)) == 0:
            os.rmdir(path_missing)
        else:
            pass
    except Exception:
        pass
    else:
    continue

在本例中，如何修改此代码以将目录名与正则表达式进行比较。（它必须忽略包含.txt文件的目录）

我在这里做了几件事，希望这个例子能有所帮助

• 我为WindowsFS编写了这篇文章，因此使用了两个路径转换函数
• 此脚本会忽略带有.txt文件的dirs，就像您实现它一样
• 此脚本将从启动脚本的目录开始，并且仅在模式匹配时打印文件名。对于上一条规则未忽略的所有子目录，都会执行此操作
• 在python中使用正则表达式，并使其针对每个目录再次编译，因此您会得到：'directory/（\S+）（\d+）（\d+）\uuud+）（\d+）（\d+）'

---

我想这还不起作用。还是这样？如果粘贴的脚本中没有选项卡，则files变量将为空。您还没有将目录或文件名与模式进行比较。我做了其他事情，使用os.path.split（part1）[1]将路径分割为字符串，然后通过re.search将其与模式进行比较，结果成功了：）但多亏了您，我有了一个简单的想法；）

import os
import re

def createEscapedPattern(path,pattern):
    newPath = os.path.normpath(path)
    newPath = newPath.replace("\\","\\\\\\\\")
    return newPath + "\\\\\\\\" +  pattern

def createEscapedPath(path):
    newPath =  os.path.normpath(path)
    return newPath.replace("\\","\\\\")

src = 'C:\\Home\\test'
path_patter = '(\S+)_(\d+)_(\d+)_(\d+)__(\d+)_(\d+)_(\d+)$'
p = re.compile(createEscapedPattern(src,path_patter))
for dir, dirs, files in os.walk(src):
    if any(f.endswith('.txt') for f in files):
        dirs[:] = []
        continue
    if any(p.match(createEscapedPath(dir)) for f in files):
        for f in files:
            print createEscapedPath(dir + "/" + f)
    p = re.compile(createEscapedPattern(dir,path_patter))