如何在另一个函数中使用函数？python

我正在努力做一场比赛，我真的被卡住了。问题是我不知道如何正确使用面向对象编程。程序应启动gameboard功能 每次当数字不等于arv时。它应返回带有一个“O”的新板 少一点

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当您只需要一个对象实例时，使用面向对象编程往往会使程序过于复杂。我建议只有一个主要功能

尽管如此，我还是修改了你的程序。请尝试自己查找更改，因为我懒得解释它们，抱歉

from random import randint
import time

class Game():    
    def __init__(self):
        pass

    def beginning(self):
        print("How are you, and why are you playing my game?")
        bla = str(input())
        time.sleep(2)
        print("Hello," + bla + ", I am glad to see you!")
        time.sleep(2)
        print("Anyways, the you have to guess a number from 1-20")
        self.__board = ["O","O","O","O","O"]


    def gameboard(self):
        print(self.__board)
        self.__board.pop()
        return self.__board   

    def game(self):
        number = randint(1,20)
        print(number)
        x = 1
        while 5 > x:
            arv = input()
            self.arv__ = arv
            if arv == number:
                print("Lucky")
                break
            elif arv != number:
                print ("haha, try again")
                print("one life gone")
                self.gameboard()
                print(self.__board)
            x += 1

def Main():
    math = Game()
    math.beginning()
    math.game()


Main()

以下是您的程序版本，它避免了OO，并且更加简化：

from random import randint

lives = 5
print("Guess a number from 1 to 20")
number = randint(1, 20)
while (lives > 1 and number != int(input())):
    print("incorrect")
    print("lives: " + "O" * lives)
    lives -= 1

if lives == 0:
    print("The number was actually " + str(number))
else:
    print("You were right")

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赛尔夫。还有多少生命？为什么你需要它成为一个列表？你的问题是什么？@BrenBarn请仔细阅读。。。“问题是我不知道如何正确使用面向对象编程”

from random import randint

lives = 5
print("Guess a number from 1 to 20")
number = randint(1, 20)
while (lives > 1 and number != int(input())):
    print("incorrect")
    print("lives: " + "O" * lives)
    lives -= 1

if lives == 0:
    print("The number was actually " + str(number))
else:
    print("You were right")