Python 如何附加dict中的列表？

我有一本字典，里面有类似于

'0/RP0'：['NCS1K4-CNTLR']

的条目。对于每个条目，我必须向值中添加另一个字符串。例如，添加

'OPERATIONAL'

会导致

'0/RP0'：['NCS1K4-CNTLR'，'OPERATIONAL']

。我需要对完整的字典执行此操作，并有一个要附加的值列表

下面我有两本字典

new_dict =
{'0/RP0': ['NCS1K4-CNTLR'], '0/PM1': ['NCS1K4-2KW-AC'], '0/PM0': ['NCS1K4-2KW-AC'], '0/FT2': ['NCS1K4-FAN'], '0/FT0': ['NCS1K4-FAN'], '0/FT1': ['NCS1K4-FAN']}

new_dict_1=   
{'0/RP0': ['OPERATIONAL'], '0/PM1': ['OPERATIONAL'], '0/PM0': ['FAILED'], '0/FT2': ['OPERATIONAL'], '0/FT0': ['OPERATIONAL'], '0/FT1': ['OPERATIONAL']}

我希望输出如下所示

{'0/RP0': ['NCS1K4-CNTLR','OPERATIONAL'], '0/PM1': ['NCS1K4-2KW-AC','OPERATIONAL'], '0/PM0': ['NCS1K4-2KW-AC','OPERATIONAL'], '0/FT2': ['NCS1K4-FAN','OPERATIONAL'], '0/FT0': ['NCS1K4-FAN','FAILED'], '0/FT1': ['NCS1K4-FAN','OPERATIONAL']}

---

您可以使用

zip（）

方法，但正如前面所提到的：Python中的字典是无序的，因此代码中可能还有一些地方需要更改

In [14]: my_dict = {'ak': ['av'], 'bk': ['bv']}

In [15]: my_list = ['a1v', 'b1v']

In [16]: for element in zip(my_dict, my_list):
    ...:     my_dict[element[0]].append(element[1])
    ...:     

In [17]: my_dict
Out[17]: {'ak': ['av', 'a1v'], 'bk': ['bv', 'b1v']}

不要被结果误导，它也可能是

{'ak'：['av'，'b1v']，'bk'：['bv'，'a1v']}

最有可能的情况是，您需要两个DICT，并用类似以下的东西将其压缩：

In [18]: my_dict = {'ak': ['av'], 'bk': ['bv']}

In [19]: my_dict_2 = {'ak': ['a1v'], 'bk': ['b2v']}

In [20]: for element in zip(my_dict, my_dict_2):
    ...:     my_dict[element[0]].append(my_dict_2[element[1]][0])
    ...:     

In [21]: my_dict
Out[21]: {'ak': ['av', 'a1v'], 'bk': ['bv', 'b2v']}

---

如果您有两个字典，一个带有列表，另一个带有要附加的字符串，则可以使用python dict.keys函数

dict_of_lists = {...}
dict_to_append ={...}
for key in dict_of_lists.keys():
    dict_of_lists[key].append(dict_of_keys[key])

---

如果第二个dict包含列表，您可能希望使用extent而不是append。

拾取注释，您的第二个dict可以很容易地与第一个dict合并：

dict1 = {'0/RP0': ['NCS1K4-CNTLR'], '0/PM1': ['NCS1K4-2KW-AC'], '0/PM0': ['NCS1K4-2KW-AC'], '0/FT2': ['NCS1K4-FAN'], '0/FT0': ['NCS1K4-FAN'], '0/FT1': ['NCS1K4-FAN']}

dict2 = {'0/RP0': ['OPERATIONAL'], '0/PM1': ['OPERATIONAL'], '0/PM0': ['FAILED'], '0/FT2': ['OPERATIONAL'], '0/FT0': ['OPERATIONAL'], '0/FT1': ['OPERATIONAL']}

for k in dict1.keys():
    if k in dict2:
        dict1[k].append(dict2[k][0])

print(dict1)

给出：

{'0/RP0': ['NCS1K4-CNTLR', 'OPERATIONAL'], '0/PM1': ['NCS1K4-2KW-AC', 'OPERATIONAL'], '0/PM0': ['NCS1K4-2KW-AC', 'FAILED'], '0/FT2': ['NCS1K4-FAN', 'OPERATIONAL'], '0/FT0': ['NCS1K4-FAN', 'OPERATIONAL'], '0/FT1': ['NCS1K4-FAN', 'OPERATIONAL']}

---

请注意，

dict2[k][0]

是附加的，否则我们将附加一个列表而不是字符串。

字典理解可能比循环更有效。下面的方法还将通过

if

语句检查键是否存在替换为

dict.get

默认值

dict1 = {'0/RP0': ['NCS1K4-CNTLR'], '0/PM1': ['NCS1K4-2KW-AC'], '0/PM0': ['NCS1K4-2KW-AC'], '0/FT2': ['NCS1K4-FAN'], '0/FT0': ['NCS1K4-FAN'], '0/FT1': ['NCS1K4-FAN']}

dict2 = {'0/RP0': ['OPERATIONAL'], '0/PM1': ['OPERATIONAL'], '0/PM0': ['FAILED'], '0/FT2': ['OPERATIONAL'], '0/FT0': ['OPERATIONAL'], '0/FT1': ['OPERATIONAL']}

dict1_new = {k: v + dict2.get(k, []) for k, v in dict1.items()}

# {'0/FT0': ['NCS1K4-FAN', 'OPERATIONAL'],
#  '0/FT1': ['NCS1K4-FAN', 'OPERATIONAL'],
#  '0/FT2': ['NCS1K4-FAN', 'OPERATIONAL'],
#  '0/PM0': ['NCS1K4-2KW-AC', 'FAILED'],
#  '0/PM1': ['NCS1K4-2KW-AC', 'OPERATIONAL'],
#  '0/RP0': ['NCS1K4-CNTLR', 'OPERATIONAL']}

---

字典是无序的；如何确定附录的顺序？您的列表应该是一个字典，使用与您的

新dict

相同的键，否则无法将列表元素绑定到字典值。如果我将列表作为具有相同键值的dict。你能告诉我密码吗。示例：{'0/RP0'：['OPERATIONAL']，'0/PM1'：['OPERATIONAL']，'0/PM0'：['FAILED']，'0/FT2'：['OPERATIONAL']，'0/FT0'：['OPERATIONAL']，'0/FT1'：['OPERATIONAL']}