Python 单元测试获取绝对值
我对django很陌生,还没写测试。我目前正在做一个有两个模型的项目,项目和技术。项目模型与技术模型存在多对多关系。我有一个覆盖get_queryset方法的视图。在我的报道中,这种方法是我唯一的失误。我正在寻找关于如何为这种方法编写单元测试的指导。谢谢你抽出时间回答我的问题 models.pyPython 单元测试获取绝对值,python,django,unit-testing,testing,Python,Django,Unit Testing,Testing,我对django很陌生,还没写测试。我目前正在做一个有两个模型的项目,项目和技术。项目模型与技术模型存在多对多关系。我有一个覆盖get_queryset方法的视图。在我的报道中,这种方法是我唯一的失误。我正在寻找关于如何为这种方法编写单元测试的指导。谢谢你抽出时间回答我的问题 models.py from django.db import models from django.template.defaultfilters import slugify from django.urls im
from django.db import models
from django.template.defaultfilters import slugify
from django.urls import reverse
class Technologies(models.Model):
name = models.CharField(max_length=64, unique=True)
slug = models.SlugField()
def __str__(self):
return self.slug
def save(self, *args, **kwargs):
self.slug = slugify(self.name)
super(Technologies, self).save(*args, **kwargs)
class Project(models.Model):
title = models.CharField(max_length=64)
description = models.CharField(max_length=128)
repo = models.URLField()
slug = models.SlugField()
image = models.ImageField(
upload_to='project_images',
default='project_images/default_project.png')
technologies = models.ManyToManyField(Technologies)
def __str__(self):
return self.title
def save(self, *args, **kwargs):
self.slug = slugify(self.title)
super(Project, self).save(*args, **kwargs)
def get_absolute_url(self):
return reverse("projects:detail", kwargs={"slug": self.slug})
views.py
from django.views.generic import DetailView, ListView
from .models import Project
class ProjectsListView(ListView):
model = Project
class ProjectDetailView(DetailView):
model = Project
class TechnologiesListView(ListView):
model = Project
allow_empty = False # If list is empty 404
def get_queryset(self):
return Project.objects.filter(technologies__slug=self.kwargs['slug'])
url.py
from django.urls import path
from . import views
app_name = "projects"
urlpatterns = [
path('', view=views.ProjectsListView.as_view(), name='list'),
path('<slug>', view=views.ProjectDetailView.as_view(), name='detail'),
path('tagged/<slug>', view=views.TechnologiesListView.as_view(), name='tech_list'),
]
test_views.py
import pytest
from django.test import RequestFactory
from django.urls import reverse
from mixer.backend.django import mixer
from projects.views import ProjectDetailView, ProjectsListView, TechnologiesListView
@pytest.mark.django_db
class TestProjectViews:
def test_projects_by_technologies_view(self):
tech = mixer.blend('projects.Technologies')
path = reverse('projects:tech_list', kwargs={'slug': tech.slug})
request = RequestFactory().get(path)
response = TechnologiesListView.as_view()(request)
assert response.status_code == 200, 'Should be status code 200'
当我运行此测试时,我得到:
def get_queryset(self):
> return Project.objects.filter(technologies__slug=self.kwargs['slug'])
E KeyError: 'slug'
这是因为KWARG不在从请求工厂生成的请求中吗?或者这是一个数据库问题?在这一点上,我感到非常困惑和困惑,我真的很感激任何明智的话。写下你的问题能够更好地解决问题,真是太神奇了。这是我的解决办法
def测试项目按技术视图(自):
self.tech=mixer.blend('projects.Technologies'))
self.proj=mixer.blend(项目,技术=self.tech)
self.path=reverse('projects:tech_list',kwargs={'slug':self.tech.slug})
self.request=RequestFactory().get(self.path)
self.response=TechnologiesListView.as_view()(self.request,slug=self.tech.slug)
断言self.response.status_code==200,“应为状态代码200”
def get_queryset(self):
> return Project.objects.filter(technologies__slug=self.kwargs['slug'])
E KeyError: 'slug'