Python 使用if语句打印函数

我已经创建了一个if语句函数。用这种方式，我应该打印最大数量的输入（请检查我的代码）。但是，由于代码本身不应该有任何错误，我仍然无法打印出最大的_数字。你能帮我一下吗

我尝试过在函数外部编写print（）语句，然后在函数内部，在每个if行中也输入print（最大的_数），但仍然没有任何更改

Number_1 = int(input("Please type your 1st number: "))
Number_2 = int(input("Please type your 2nd number: "))
Number_3 = int(input("Please type your 3rd number: "))
Number_4 = int(input("Please type your 4th number: "))
Number_5 = int(input("Please type your 5th number: "))
Number_6 = int(input("Please type your 6th number: "))

def largest(Number_1, Number_2, Number_3, Number_4, Number_5, Number_6):
    if (Number_1 >= Number_2) and (Number_1 >= Number_3) and (Number_1 >= Number_4) and (Number_1 >= Number_5) and (Number_1 >= Number_6):
        largest_Number == Number_1;
    else:
        if (Number_2 >= Number_1) and (Number_2 >= Number_3) and (Number_2 >= Number_4) and (Number_2 >= Number_5) and (Number_2 >= Number_6):
            largest_Number == Number_2
        else:
            if (Number_3 >= Number_1) and (Number_3 >= Number_2) and (Number_3 >= Number_4) and (Number_3 >= Number_5) and (Number_3 >= Number_6):
                largest_Number == Number_3
            else:
                if (Number_4 >= Number_1) and (Number_4 >= Number_2) and (Number_4 >= Number_3) and (Number_4 >= Number_5) and (Number_4 >= Number_6):
                    largest_Number == Number_4
                else:
                    if (Number_5 >= Number_1) and (Number_5 >= Number_2) and (Number_5 >= Number_3) and (Number_5 >= Number_4) and (Number_5 >= Number_6):
                        largest_Number == Number_5
                    else:
                        if (Number_6 >= Number_1) and (Number_6 >= Number_2) and (Number_6 >= Number_3) and (Number_6 >= Number_4) and (Number_6 >= Number_5):
                            largest_Number == Number_6
                            print(largest_Number)

有几个错误：

您的代码具有

最大\u编号==编号\u 6

（等），但

=

检查是否相等。您需要

maximust\u Number=Number\u 6（等）

最后一个

print（）

嵌套在最后一个

if

语句中。你想把它带到最外层

此外，使用

max（）

函数可以大大简化代码，但由于您将其称为“if语句函数”，我认为这是故意的。如果没有，您可以执行以下操作：

Number_1 = int(input("Please type your 1st number: "))
Number_2 = int(input("Please type your 2nd number: "))
Number_3 = int(input("Please type your 3rd number: "))
Number_4 = int(input("Please type your 4th number: "))
Number_5 = int(input("Please type your 5th number: "))
Number_6 = int(input("Please type your 6th number: "))

def largest(Number_1, Number_2, Number_3, Number_4, Number_5, Number_6):
    largest_number = max([Number_1, Number_2, Number_3, Number_4, Number_5, Number_6])
    print(largest_number)

largest(Number_1, Number_2, Number_3, Number_4, Number_5, Number_6)

---

应将==替换为=（赋值运算符）

---

在这里，下面的_laregest==变量是从给定的输入数字中获取最大数字的更简洁的代码（将数字存储在列表中，如下所示）：

输入

输出

Please type your numbers1 2 3 4 5 6

[1, 2, 3, 4, 5, 6]

要获取最大数量，请执行以下操作：

max(a)

输出：

6

---

欢迎使用StackOverflow&希望这对您有所帮助

def largest(Number_1, Number_2, Number_3, Number_4, Number_5, Number_6):
    if (Number_1 >= Number_2) and (Number_1 >= Number_3) and (Number_1 >= Number_4) and (Number_1 >= Number_5) and (Number_1 >= Number_6):
        largest_Number = Number_1;
    else:
        if (Number_2 >= Number_1) and (Number_2 >= Number_3) and (Number_2 >= Number_4) and (Number_2 >= Number_5) and (Number_2 >= Number_6):
            largest_Number = Number_2
        else:
            if (Number_3 >= Number_1) and (Number_3 >= Number_2) and (Number_3 >= Number_4) and (Number_3 >= Number_5) and (Number_3 >= Number_6):
                largest_Number = Number_3
            else:
                if (Number_4 >= Number_1) and (Number_4 >= Number_2) and (Number_4 >= Number_3) and (Number_4 >= Number_5) and (Number_4 >= Number_6):
                    largest_Number = Number_4
                else:
                    if (Number_5 >= Number_1) and (Number_5 >= Number_2) and (Number_5 >= Number_3) and (Number_5 >= Number_4) and (Number_5 >= Number_6):
                        largest_Number = Number_5
                    else:
                        if (Number_6 >= Number_1) and (Number_6 >= Number_2) and (Number_6 >= Number_3) and (Number_6 >= Number_4) and (Number_6 >= Number_5):
                            largest_Number = Number_6
    print(largest_Number)

提示很少，您可以在代码中使用

if…elif..else

def largest(Number_1, Number_2, Number_3, Number_4, Number_5, Number_6):
    if (Number_1 >= Number_2) and (Number_1 >= Number_3) and (Number_1 >= Number_4) and (Number_1 >= Number_5) and (Number_1 >= Number_6):
        largest_Number = Number_1;
    elif (Number_2 >= Number_1) and (Number_2 >= Number_3) and (Number_2 >= Number_4) and (Number_2 >= Number_5) and (Number_2 >= Number_6):
        largest_Number = Number_2
    elif (Number_3 >= Number_1) and (Number_3 >= Number_2) and (Number_3 >= Number_4) and (Number_3 >= Number_5) and (Number_3 >= Number_6):
        largest_Number = Number_3
    elif (Number_4 >= Number_1) and (Number_4 >= Number_2) and (Number_4 >= Number_3) and (Number_4 >= Number_5) and (Number_4 >= Number_6):
        largest_Number = Number_4
    elif (Number_5 >= Number_1) and (Number_5 >= Number_2) and (Number_5 >= Number_3) and (Number_5 >= Number_4) and (Number_5 >= Number_6):
        largest_Number = Number_5
    elif (Number_6 >= Number_1) and (Number_6 >= Number_2) and (Number_6 >= Number_3) and (Number_6 >= Number_4) and (Number_6 >= Number_5):
        largest_Number = Number_6
    print(largest_Number)

---

一个小问题是你的

print（maximust_Number）

应该在

if

条件之外。

所有该函数都可以替换为

def-maximust（*args）：print（maximum（args））

maximust（Number_1，Number_2，…，Number_6）@roganjosh你是对的，但OP称之为“if语句函数”，所以这可能是一个有意使用if语句的练习。只是一个提示，在这种情况下，我会以相反的方式使用条件检查，以避免不必要的嵌套。i、 e.首先检查

False

条件，如果是，则返回。然后，您可以在初始if的相同级别编写

True

大小写，而无需使用

else

子句。问题是它仍然不想打印答案（你调用函数了吗？比如我该怎么做？

最大值（Number_1、Number_2、Number_3、Number_4、Number_5、Number_6）

你知道定义函数和调用函数之间的区别吗？我需要像我已经做的那样对输入进行编码，并从中继续，仍然感谢您提供了最好的解决方案。但是我遇到了一个关于max（）的问题因为它在我的情况下不起作用（不打印最大值）…在您的情况下，数字是离散的，

max

函数在列表上工作。如果问题解决，请传递一个值列表并调用

max

函数。请向上投票并接受答案

def largest(Number_1, Number_2, Number_3, Number_4, Number_5, Number_6):
    if (Number_1 >= Number_2) and (Number_1 >= Number_3) and (Number_1 >= Number_4) and (Number_1 >= Number_5) and (Number_1 >= Number_6):
        largest_Number = Number_1;
    elif (Number_2 >= Number_1) and (Number_2 >= Number_3) and (Number_2 >= Number_4) and (Number_2 >= Number_5) and (Number_2 >= Number_6):
        largest_Number = Number_2
    elif (Number_3 >= Number_1) and (Number_3 >= Number_2) and (Number_3 >= Number_4) and (Number_3 >= Number_5) and (Number_3 >= Number_6):
        largest_Number = Number_3
    elif (Number_4 >= Number_1) and (Number_4 >= Number_2) and (Number_4 >= Number_3) and (Number_4 >= Number_5) and (Number_4 >= Number_6):
        largest_Number = Number_4
    elif (Number_5 >= Number_1) and (Number_5 >= Number_2) and (Number_5 >= Number_3) and (Number_5 >= Number_4) and (Number_5 >= Number_6):
        largest_Number = Number_5
    elif (Number_6 >= Number_1) and (Number_6 >= Number_2) and (Number_6 >= Number_3) and (Number_6 >= Number_4) and (Number_6 >= Number_5):
        largest_Number = Number_6
    print(largest_Number)